Answer: -
Mass of Hydrated KAl(SO₄)₂ = 2.0 g
Molar mass of anhydrous KAl(SO₄)₂ = 258.20 g/ mol
Mass of of anhydrous KAl(SO₄)₂ = mass of the 2nd heating = A
The mass of water released = mass of the Aluminum Cup + 2.0 grams of KAl(SO₄)₂ - mass of the 2nd heating
= H g
Moles of water released = 
Moles of anhydrous KAl(SO₄)₂ = 
Required ratio = 
You can answer that by looking at how much water got remained atop. The more water atop means less permeability. If something is permeable it let the water diffuse. So the answer is silt.
Answer:
b. 2-4
Explanation:
Look at the slope of the line, between 0-2 and 4-6 the slope is only 10, but between 2-4 the slope is 20, so that's when the temperature is changing the fastest. In the same time it took for the water to increase by 20 degrees between 0-2 and 4-6, the temperature of the water increased by 40 degrees between 2-4 so that's when the change is the fastest.
The balanced chemical equation for the reaction is as follows
Mg(OH)₂ + 2HCl ---> MgCl₂ + 2H₂O
molar ratio of HCl to MgCl₂ is 2:1
There's excess Mg(OH)₂ therefore HCl is the limiting reactant.
the amount of product formed is determined by the amount of limiting reactant present
so when 2 mol of HCl reacts - 1 mol of MgCl₂ is produced
therefore when 4.66 mol of HCl reacts - 1/2 x 4.66 = 2.33 mol of MgCl₂ is produced
answer is 2.33 mol of MgCl₂
