All categories

3 years ago

In a solution, the substance that changes phase is the _, while the substance that does not change phase is the.

Chemistry

2 answers:

iren [92.7K]3 years ago

6 0

Phase change is the solute
the one that doesn't phase change is the solvent.
A

Nezavi [6.7K]3 years ago

5 0

Answer: solute, solvent

Explanation: Solute is the substance which is present in smaller quantity and solvent is the substance which is present in larger quantity.

Thus when solid solute is mixed with the liquid solvent, after the dissolution of the former, it will change its state from solid to liquid but the phase of the solvent is kept the same.

Thus , In a solution, the substance that changes phase is the <u>solute</u>, while the substance that does not change phase is the <u>solvent</u>.

You might be interested in

Please help me out here please

zepelin [54]

I would say G sorry if it’s not right

3 0

3 years ago

Read 2 more answers

Type a sentence or two about early models of telephones. Include its description.

Evgesh-ka [11]

Answer:early models of telephones were used with a twirl of numbers

Explanation:

Not advanced technology

8 0

2 years ago

Read 2 more answers

GarryVolchara [31]

Answer:

The value of the Golden Igloo is $227.4 million.

Explanation:

First, we need to find the inner and the outer volume of the half-spherical shell:

$V_{i} = \frac{1}{2}*\frac{4}{3}\pi r_{i}^{3}$

$V_{o} = \frac{1}{2}*\frac{4}{3}\pi r_{o}^{3}$

The total volume is given by:

$V_{T} = V_{o} - V_{i}$

Where:

$V_{i}$ : is the inner volume

$r_{i}$ : is the inner radius = 1.25/2 = 0.625 m

$V_{o}$ : is the outer volume

$r_{o}$ : is the outer radius = 1.45/2 = 0.725 m

Then, the total volume of the Igloo is:

$V_{T} = \frac{2}{3}\pi r_{o}^{3} - \frac{2}{3}\pi r_{i}^{3} = \frac{2}{3}\pi [(0.725 m)^{3} - (0.625 m)^{3}] = 0.29 m^{3}$

Now, by using the density we can find the mass of the Igloo:

$m = 19.3 \frac{g}{cm^{3}}*0.29 m^{3}*\frac{(100 cm)^{3}}{1 m^{3}} = 5.60 \cdot 10^{6} g$

Finally, the value (V) of the antiquity is:

$V = \frac{\$ 1263}{oz}*5.60 \cdot 10^{6} g*\frac{1 oz}{31.1034768 g} = \$ 227.4 \cdot 10^{6}$

Therefore, the value of the Golden Igloo is $227.4 million.

I hope it helps you!

8 0

2 years ago

What is included in a compaarative investigation

Minchanka [31]

a scientific question

6 0

3 years ago

5. Durante un estudio de la velocidad de la reacción A2(g) + 3B2(g)  2 AB3(g), se observa que en un recipiente cerrado que cont

weqwewe [10]

Answer:

a) Speed of the reaction = 0.002083 mol/L.s

b) The rate of disappearance of A₂ during this period of time = 0.002083 mol/L.s

c) The rate of appearance of AB₃ = 0.004167 mol/L.s

Explanation:

English Translation

During a study of the reaction rate

A₂ (g) + 3B₂ (g) → 2 AB₃ (g),

it is observed that in a closed container containing a certain amount of A₂ and 0.75 mol / L of B₂, the concentration B₂ decreases to 0.5 mol / L in 40 seconds.

a) What is the speed of the reaction?

b) What is the rate of disappearance of A₂ during this period of time?

c) What is the rate of appearance of AB₃?

Solution

The rate of a chemical reaction is defined as the time rate at which a reactant is used up or the rate at which a product is formed.

It is the rate of change of the concentration of a reactant (rate of decrease of the concentration of the reactant) or a product (rate of increase in the concentration of the product) with time.

Mathematically, for a balanced reaction

aA → bB

Rate = -(1/a)(ΔA/Δt) = (1/b)(ΔB/Δt)

The minus sign attached to the change of the reactant's concentration indicates that the reactant's concentration decreases.

And the coefficients of each reactant and product in the balanced reaction normalize the rate of reaction for each of them

So, for our given reaction,

A₂ (g) + 3B₂ (g) → 2 AB₃ (g)

Rate = -(ΔA₂/Δt) = -(1/3)(ΔB₂/Δt) = (1/2)(ΔAB₃/Δt)

a) Speed of the reaction = Rate of the reaction

But we are given information on the change of concentration of B₂

Change in concentration of B₂ = ΔB₂ = 0.50 - 0.75 = -0.25 mol/L

Change in time = Δt = 40 - 0 = 40 s

(ΔB₂/Δt) = (-0.25/40) = -0.00625 mol/L.s

Rate of the reaction = -(1/3)(ΔB₂/Δt) = (-1/3) × (-0.00625) = 0.002083 mol/L.s

b) The rate of disappearance of A₂ during this period of time

Recall

Rate = -(ΔA₂/Δt) = -(1/3)(ΔB₂/Δt)

-(ΔA₂/Δt) = -(1/3)(ΔB₂/Δt)

Rate of disappearance of A₂ = -(ΔA₂/Δt) = -(1/3)(ΔB₂/Δt) = (-1/3) × (-0.00625) = 0.002083 mol/L.s

c) The rate of appearance of AB₃

Recall

Rate = -(1/3)(ΔB₂/Δt) = (1/2)(ΔAB₃/Δt)

(1/2)(ΔAB₃/Δt) = -(1/3)(ΔB₂/Δt)

(ΔAB₃/Δt) = -(2/3)(ΔB₂/Δt)

rate of appearance of AB₃ = (ΔAB₃/Δt) = -(2/3)(ΔB₂/Δt) = (-2/3) × (-0.00625) = 0.004167 mol/L.s

Hope this Helps!!!

3 0

2 years ago

In a solution, the substance that changes phase is the _____, while the substance that does not change phase is the____.

In a solution, the substance that changes phase is the _, while the substance that does not change phase is the.