yes that's true 6g is larger
Answer:
Part A:
Time taken by the snake to reach its top speed is 1.28571 sec.
Part B:
Snake travels 2.0828 m in that time
Part C:
Mongoose have a chance to catch the black mamba
Explanation:
Part A:
According to first equation of motion:
v_f is top speed
v_i is initial or minimum speed
t is time
a is acceleration
Time taken by the snake to reach its top speed is 1.28571 sec
Part B:
According to Second equation of motion:
v_i=0
Snake travels 2.0828 m in that time
Part C:
Distance covered by black mamba is 2.0828 m which is less than its length 3.12 m
2.0828 m<3.12 m
Mongoose have a chance to catch the black mamba
Answer:
terrestrial ecosystem and pond ecosystem is an aquatic ecosytem, hence both their abiotic and biotic components would be different.
Explanation:
Answer: The observer must walk 0.2897m towards either speaker.
Explanation:
Let us make distance between the two speakers to be =D
frequency emitted by the two speakers in phase=f
v= speed of sound, 343 m/s
λ=wavelength
---- solving for λ, wavelength, using the equation λ=v/f. 343/296
= 1.15878m
Also destructive interference is given as
⎮d1-d2⎮=λ/2
Because the observer should be able to walk far enough to make the distance to one speaker differ from the distance to the other speaker by ½ wavelength.
This will give us
d1-d2= 1.15878 /2
d1-d2=0.5794m
For the distance moved on either side, we have D/2
Therefore 0.5794/2=distance to move on either side. Giving us
0.2897m
In conclusion, This means that the observer has to walk so as to be 0.5794m closer to one speaker from another; this means walking 0.2897m towards either speaker.