Answer:
E = 10⁵ J
Explanation:
given,
Power, P = 100 TW
= 100 x 10¹² W
time, t = 1 ns
= 1 x 10⁻⁹ s
The energy of a single pulse is:-
Energy = Power x time
E = P t
E = 100 x 10¹² x 1 x 10⁻⁹
E = 10⁵ J
The energy contained in a single pulse is equal to 10⁵ J
The orbiting velocity of the satellite is 4.2km/s.
To find the answer, we need to know about the orbital velocity of a satellite.
<h3>What's the expression of orbital velocity of a satellite?</h3>
- Mathematically, orbital velocity= √(GM/r)
- r = radius of the orbital, M = mass of earth
<h3>What's the orbital velocity of a satellite orbiting earth with a radius 3.57 times the earth radius?</h3>
- M= 5.98×10²⁴ kg, r= 3.57× 6.37×10³ km = 22.7×10⁶m
- Orbital velocity= √(6.67×10^(-11)×5.98×10²⁴/22.7×10⁶)
=4.2km/s
Thus, we can conclude that the orbiting velocity of the satellite is 4.2km/s.
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Magic magic and more magic
For velocity vs Time graphs, the displacement of the object from 2 seconds to 6 seconds is 30 m.
<h3>What is displacement?</h3>
The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.
In velocity time graphs, the displacement is the area under the curve of the graph on the x axis.
'
A line starts at (0, 2) and ends at (6, 8) in v-t graph
Displacement is equal to the area of a triangle and a rectangle formed under the line.
Area = 1/2 base x height + length x breadth
Area = 1/2 x 6x 6 + 6x2
Area = 18 +12
Area = 30 m
Thus, the displacement is 30 m.
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