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pashok25 [27]
2 years ago
6

5 Ohm 3 Ohm 2 Ohm R=?​

Physics
1 answer:
Tema [17]2 years ago
5 0

Answer:

6.2 ohm

Explanation:

Let R1 = 5 ohm

R2= 3 ohm

R3= 2 ohm

Since R3 and R2 are parallel then net resistance R' is given by

1/R' = 1/R2 + 1/R3

1/R' = 1/3 + 1/2

1/R' = 5/6

then

R' = 6/5 = 1.2 ohm

Now R1 and R' are in series, so

R = R1 + R'

R = 5 + 1.2

R = 6.2 ohm

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Answer:

A. polymerization

Explanation:

Synthetic plastics are made by linking many simple carbon molecules together to form much larger molecules. This process is called polymerization.

Synthetic or artifical giant molecules consists of synthetic polymers such as plastics, elastomers etc. They are made up of simple monomers which links to form the complex and giant structure.

Monomers are the simplest unit of polymers. Polymers have very great sizes. The size mkaes their structure quite complex. This makes the molecules more disposed in a regular pattern with respect to one another.

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2 years ago
Two coherent sources of radio waves, A and B, are 5.00 meters apart. Each source emits waves with wavelength 6.00 meters. Consid
Korolek [52]

Answer:

a

    z= 2.5 \ m

b

   z =  (1 \ m ,  4 \ m )

Explanation:

From the question we are told that

     Their distance apart is  d =  5.00 \ m

      The  wavelength of each source wave \lambda =  6.0 \ m

Let the distance from source A  where the construct interference occurred be z

Generally the path difference for constructive interference is

              z - (d-z) =  m \lambda

Now given that we are considering just the straight line (i.e  points along the line connecting the two sources ) then the order of the maxima m =  0

  so

        z - (5-z) =  0

=>     2 z - 5 =  0

=>     z= 2.5 \ m

Generally the path difference for destructive  interference is

           |z-(d-z)| = (2m + 1)\frac{\lambda}{2}

=>         |2z - d |= (0 + 1)\frac{\lambda}{2}

=>        |2z - d| =\frac{\lambda}{2}

substituting values

          |2z - 5| =\frac{6}{2}

=>      z  =  \frac{5 \pm 3}{2}

So  

      z =  \frac{5 + 3}{2}

      z =  4\ m

and

      z =  \frac{ 5 -3 }{2}

=>   z =  1 \ m

=>    z =  (1 \ m ,  4 \ m )

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