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neonofarm [45]
3 years ago
5

In a waterfall, water falls 60 m. Assume all the potential energy change increases its enthalpy (or internal energy, in this cas

e they change by the same amount because this is an incompressible liquid). The specific heat capacity for water is 4184 J/kg·°C. Calculate the temperature rise of the water in °C. (8 points)
Physics
1 answer:
iVinArrow [24]3 years ago
4 0

Answer:

The  temperature rise of the water is = 0.14 °c

Explanation:

Height = 60 m

Potential energy change ΔP = m gh

ΔP =  m × 9.81 × 60

ΔP = (588.6 × m) Joule

Since the Potential energy change is equal to the internal energy change or Enthalpy change.

ΔP = ΔH

Since  ΔH = m × C × ΔT

⇒ ΔP = m × C × ΔT

Put all the values in above formula we get

⇒ 588.6 × m = m × 4184 × ΔT

⇒ ΔT= 0.14 °c

Therefore the  temperature rise of the water is = 0.14 °c

 

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