By how much will the water temperature increases if 1046 J of heat energy are added. The specific heat of water is 4.184 J/g • °
1 answer:
Answer:
Option A
250 degrees Celcius
Explanation:
If 1046J of heat energy is added to water, the water will experience a rise in temperature, at a rate that is directly proportional to its specific heat capacity.
Mathematically, this can be seen as
Where C = specific heat of water = 4.184 J/g • °C.
Q = heat energy = 1046 J
Therefore, the increase in temperature that will be experienced, is for 250 degrees Celcius
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Answer:
B. CA, 14
Explanation:
Atoms of elements contain small particles known as electrons, neutrons, and protons. The nucleus of an atom is made up of neutrons and protons which are at the center of the atom. Electrons on the other hand surrounds the nucleus. Electron has negative charge while proton has a positive charge. The number of neutrons is equivalent to the number of protons . In addition, the number of protons is equal to mass number minus the number of electrons.
For the compound , it can be broken down into
and
. Its ion has a mass of 34 and 18 electrons which means it has already lost 2 electrons.
Therefore:
For the given element, the number of electrons is 18+2 = 20 electrons.
The number of protons = 34 - 20 = 14.
And the number of neutrons is 14.
Only option B has the correct answer.