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Greeley [361]
3 years ago
10

Gold has a density of 19.32 is this a chemical change or physical change

Chemistry
1 answer:
forsale [732]3 years ago
7 0

Answer:

chemical change it is melted down

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Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.
ad-work [718]

Answer:

4.62

so 5

the ratio is 2 na chlorates for 3 O2 so multiply 7 by 2/3

Explanation:

4 0
3 years ago
Osmotic pressure ____.a. occurs only in ionic solutions.b. is lower with 1 M NaCl than 1 M sucrose.c. is created using detergent
xenn [34]

Answer:

d. is the hydrostatic pressure produced on the surface of a semi-permeable membrane by osmosis.    

Explanation:

Osmosis -

It is the flow of the molecules of solvent from a region of higher concentration towards the region of lower concentration via a semipermeable membrane , is known as osmosis.

Osmotic pressure -

It refers to the minimum amount of pressure , which is required to be applied to the solution in order to avoid the flow of pure solvent via the semipermeable membrane , is referred to as osmotic pressure.

Or in simple terms ,

Osmotic pressure is the pressure applied to resists the process of osmosis.

Hence ,

From the given options in the question,

The correct option regarding osmotic pressure is d.

7 0
3 years ago
A new penny has a mass of 2.49 g and a volume of 0.349cm3. The density of copper is 8.94 g/mLA)Is the penny made of pure copper?
yawa3891 [41]

Answer:

Zinc metal might be mixed with the copper.

Explanation:

Density is defined as mass of the substance present in the unit volume of the substance.

Mass=\frac{Mass}{Volume}

Density of pure copper = d = 8.94 g/mL = 8.94 g/cm^3

1 mL = 1 cm^3

Mass of the copper penny = M = 2.49 g

Volume of the copper penny = V = 0.349 cm^3

Density of the copper penny = d

d=\frac{M}{V}=\frac{2.49 g}{0.349 cm^3}=7.135 g/cm^3

Density of pure copper > Density of zinc > Density of penny

8.94 g/cm^3>7.14 g/cm^3>7.135 g/cm^3

The metal mixed with copper is zinc to make a penny . This is so because all the other metal given have higher value of density which will increase the density of the copper penny if they were present.

But here the density of the copper penny is smaller than density of pure copper which means that less denser metal than copper is also added in the penny.

3 0
2 years ago
How has the work of chemists affected the environment over the years?
Nataly [62]

Answer:

Chemistry is one of the causes for global warming, and in some cases it can even cause certain illnesses.

8 0
3 years ago
3.0 mL of 0.02 M Fe(NO3)3 solution is mixed with 3.0 mL of 0.002 M NaNCS and diluted to the mark with HNO3 in 10 mL volumetric f
Stella [2.4K]

Answer:

The K_c for [Fe(NCS)]^{2+} formation is 5.7\times 10^2.

Explanation:

Moles=Concentration\times Volume (L)

Fe(NO_3)_3(aq)\rightarrow Fe^{3+}(aq)+3NO_3^{-}(aq)

[Fe(NO_3)_3]=0.02 M=[Fe^{3+}]

Concentration of ferric ion = [Fe^{3+}]=0.02 M

Volume of ferric solution = 3.0 mL = 0.003 L

Moles of ferric ion  =0.02 M\times 0.003 L

1 mL = 0.001 L

NaNCS(aq)\rightarrow Na^+(aq)+NCS^-(aq)

[NaNCS]=0.002 M=[NCS^-]

Concentration of NCS^- ion = [NCS^{-}]=0.002 M

Volume of NCS^- ion solution = 3.0 mL = 0.003 L

Moles of NCS^- ion= 0.002 M\times 0.003 L

Volume of nitric acid solution = 10 mL = 0.010 L

After mixing all the solution the concentration of ferric ion and NCS^- ion will change

Total volume of solution = 0.003 L + 0.003 L + 0.010 L = 0.016 L

Initial concentration of ferric ion before reaching equilibrium :

= \frac{0.02 M\times 0.003 L}{0.016 L}=0.00375 M

Initial concentration of NCS^- ion before reaching equilibrium :

= \frac{0.002 M\times 0.003 L}{0.016 L}=0.000375 M

Fe^{3+}+NCS^-\rightleftharpoons [Fe(NCS)]^{2+}

Initially:

0.00375 M    0.000375 M       0

At equilibrium :

(0.00375-x)   (0.000375-x)       x

Equilibrium concentration of [Fe(NCS)]^{2+}=x=2.5\times 10^{-4} M

The expression of equilibrium constant for formation [Fe(NCS)]^{2+} is given by :

K_c=\frac{[[Fe(NCS)]^{2+}]}{[Fe^{3+}][NCS^-]}

K_c=\frac{x}{(0.00375-x)\times (0.000375-x)}

K_c=\frac{2.5\times 10^{-4} }{(0.00375-2.5\times 10^{-4})\times (0.000375-2.5\times 10^{-4})}

K_c=5.7\times 10^2

The K_c for [Fe(NCS)]^{2+} formation is 5.7\times 10^2.

5 0
3 years ago
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