Answer:
4.62
so 5
the ratio is 2 na chlorates for 3 O2 so multiply 7 by 2/3
Explanation:
Answer:
d. is the hydrostatic pressure produced on the surface of a semi-permeable membrane by osmosis.
Explanation:
Osmosis -
It is the flow of the molecules of solvent from a region of higher concentration towards the region of lower concentration via a semipermeable membrane , is known as osmosis.
Osmotic pressure -
It refers to the minimum amount of pressure , which is required to be applied to the solution in order to avoid the flow of pure solvent via the semipermeable membrane , is referred to as osmotic pressure.
Or in simple terms ,
Osmotic pressure is the pressure applied to resists the process of osmosis.
Hence ,
From the given options in the question,
The correct option regarding osmotic pressure is d.
Answer:
Zinc metal might be mixed with the copper.
Explanation:
Density is defined as mass of the substance present in the unit volume of the substance.

Density of pure copper = d = 8.94 g/mL = 

Mass of the copper penny = M = 2.49 g
Volume of the copper penny = V = 
Density of the copper penny = d

Density of pure copper > Density of zinc > Density of penny

The metal mixed with copper is zinc to make a penny . This is so because all the other metal given have higher value of density which will increase the density of the copper penny if they were present.
But here the density of the copper penny is smaller than density of pure copper which means that less denser metal than copper is also added in the penny.
Answer:
Chemistry is one of the causes for global warming, and in some cases it can even cause certain illnesses.
Answer:
The
for
formation is
.
Explanation:


![[Fe(NO_3)_3]=0.02 M=[Fe^{3+}]](https://tex.z-dn.net/?f=%5BFe%28NO_3%29_3%5D%3D0.02%20M%3D%5BFe%5E%7B3%2B%7D%5D)
Concentration of ferric ion = ![[Fe^{3+}]=0.02 M](https://tex.z-dn.net/?f=%5BFe%5E%7B3%2B%7D%5D%3D0.02%20M)
Volume of ferric solution = 3.0 mL = 0.003 L
Moles of ferric ion 
1 mL = 0.001 L

![[NaNCS]=0.002 M=[NCS^-]](https://tex.z-dn.net/?f=%5BNaNCS%5D%3D0.002%20M%3D%5BNCS%5E-%5D)
Concentration of
ion = ![[NCS^{-}]=0.002 M](https://tex.z-dn.net/?f=%5BNCS%5E%7B-%7D%5D%3D0.002%20M)
Volume of
ion solution = 3.0 mL = 0.003 L
Moles of
ion= 
Volume of nitric acid solution = 10 mL = 0.010 L
After mixing all the solution the concentration of ferric ion and
ion will change
Total volume of solution = 0.003 L + 0.003 L + 0.010 L = 0.016 L
Initial concentration of ferric ion before reaching equilibrium :
= 
Initial concentration of
ion before reaching equilibrium :
= 
![Fe^{3+}+NCS^-\rightleftharpoons [Fe(NCS)]^{2+}](https://tex.z-dn.net/?f=Fe%5E%7B3%2B%7D%2BNCS%5E-%5Crightleftharpoons%20%5BFe%28NCS%29%5D%5E%7B2%2B%7D)
Initially:
0.00375 M 0.000375 M 0
At equilibrium :
(0.00375-x) (0.000375-x) x
Equilibrium concentration of ![[Fe(NCS)]^{2+}=x=2.5\times 10^{-4} M](https://tex.z-dn.net/?f=%5BFe%28NCS%29%5D%5E%7B2%2B%7D%3Dx%3D2.5%5Ctimes%2010%5E%7B-4%7D%20M)
The expression of equilibrium constant for formation
is given by :
![K_c=\frac{[[Fe(NCS)]^{2+}]}{[Fe^{3+}][NCS^-]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5B%5BFe%28NCS%29%5D%5E%7B2%2B%7D%5D%7D%7B%5BFe%5E%7B3%2B%7D%5D%5BNCS%5E-%5D%7D)



The
for
formation is
.