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vodomira [7]
3 years ago
14

Calculate the momentum for the 5 kg bowling ball moving at 6 m/s.

Physics
1 answer:
Serhud [2]3 years ago
3 0

Answer:

Given

mass (m) =5kg

velocity (v) =6m/s

momentum (p) =?

Form

p=mv

5kgx6m/s

p=30kg.m/s

momentum =30kg.m/s

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Confirm if this is correct or not. If it isn't correct, please correct it.
kow [346]

Answer:

d = 421.83 m

Explanation:

It is given that,

Height, h = 396.9 m

Horizontal speed, v = 46.87 m/s

We need to find the distance traveled by the ball horizontally. Let t is the time taken by the ball. Using second equation of motion for vertical direction. So,

396.9=0\times t+\dfrac{1}{2}\times 9.8 t^2\\\\t=9\ s

Now d is the distance covered by the cannonball. So,

d=vt\\\\d=46.87\times 9\\\\d=421.83\ m

Hence, this is the required solution.

3 0
3 years ago
What are two processes that transfer water into the atmosphere
Ira Lisetskai [31]
Water enters the atmosphere through evaporation, transpiration, excretion and sublimation: Transpiration is the loss of water from plant

Hope this helped you! :D
4 0
3 years ago
When two magnets are brought close together their magnetic
Gnoma [55]

Answer:

You know the saying "Opposites attract" well that is how you can remember that South and North Magnetic Poles connect.  

Explanation:

Hope this helps ya

6 0
3 years ago
The acceleration of a cart rolling down a ramp depends on __________.
zmey [24]

The angle that the cart rolls with the horizontal. The closer the ramp gets to 90 degrees the faster the cart will accelerate.

8 0
3 years ago
A trooper is moving due south along the freeway at a speed of 30.1 m/s when a red car passes the trooper. The red car moves with
romanna [79]

Answer:

The correct answer to the following question will be "41.87 m".

Explanation:

The given values are:

The speed of trooper = 30.1 \ m/s

The velocity of red car = 45.4 \ m/s

Now,

A red car goes as far as possible until the speed or velocity of the troops is the same as that of of the red car at

t=\frac{45-30}{2.7}                                                              (∵ time=\frac{distance}{time})

t=5.56 \ sec

then,

The distance covered by trooper,

t1=30\times 5.56+\frac{1}{2}\times 2.7\times (5.56)^2

   =208.33 \ m

The distance covered by red car,

= 45\times 5.56

= 250.2 \ m

Maximum distance = 250.2-208.33

                                = 41.87 \ m                                                        

6 0
3 years ago
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