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frutty [35]
4 years ago
13

The symbol used for magnetic field is:

Physics
1 answer:
Elena-2011 [213]4 years ago
6 0

Answer:

magnetic field denoted by B

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The solution is in the attachment

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3 years ago
What stands in for a "creator" in scientists view of the universe?
inessss [21]

In scientists view of the universe The creator is replace by: (B). The "Big Bang"

<h3>Meaning of Big Bang</h3>

The Big bang is a theory propagated by scientist and astronomers to replace the creator.

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In conclusion, In scientists view of the universe The creator is replace by: The "Big Bang"

Learn more about The Big Bang: brainly.com/question/10865002

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5 0
2 years ago
You are designing a system for moving aluminum cylinders from the ground to a loading dock. You use a sturdy wooden ramp that is
8_murik_8 [283]

Answer:

a = αR

Then We apply the Newton's second law of motion:

∑ F = ma

F - mg sinθ - f = ma.

F - mg sinθ - μmg cosθ = ma

Using given data we have:

F - 3217 = 470a ........................... (1)

Apply the Newton's law for rotation:

∑τ = I α

FR - (mg sinθ)R = (\frac{mR^2}{2}+mR^2)\frac{a}{R}

then: F - mg sinθ = 3ma / 2.

F - 2774 = 705a .......................... (2)

solving 1 and 2 we get:

F = 4103 N

a = 1.885 m/s²

b) In this case the time is given by:

t = \sqrt{\frac{2d}{a}} it comes from: d = v_ot+\frac{1}{2}at^2 starting from rest vo = 0

t = \sqrt{\frac{2*9}{1.885} = 3.09 s

8 0
3 years ago
A proton enters a uniform magnetic field of strength 2 T at 300 m/s. The magnetic field is oriented perpendicular to the proton’
sattari [20]

Answer:

Magnetic force, F=9.6\times 10^{-17}\ N

Explanation:

It is given that,

Magnetic field, B = 2 T

Velocity of the proton, v = 300 m/s

Charge on the proton, q=1.6\times 10^{-19}\ C

The magnetic field is oriented perpendicular to the proton’s velocity. The magnetic force on the charged particle is given by :

F=qvB\ sin\theta

The magnetic field is oriented perpendicular to the proton’s velocity, \theta=90^{\circ}

F=1.6\times 10^{-19}\times 300\times 2

F=9.6\times 10^{-17}\ N

So, the magnitude of the force that the proton experiences while it moves through the magnetic field is 9.6\times 10^{-17}\ N. Hence, this is the required solution.

7 0
3 years ago
A car starts from rest with an acceleration of 2.84 m/s2 at the instant when a second car moving with a velocity of 25.7 m/s pas
vredina [299]

Answer:

464.69 m

Explanation:

First car

s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times t+\frac{1}{2}2.84t^2\\\Rightarrow s=1.42t^2

Second car

Distance = Speed × Time

\text{Distance}=25.7t

Here, the time taken and the distance traveled will be the same

Equating the two equations

1.42t^2=25.7t\\\Rightarrow t=\frac{25.7}{1.42}\\\Rightarrow t=18.09\ s

So, the first would have to move 1.42t^2=1.42\times 18.09^2=464.69\ m in order to overtake the second car.

7 0
4 years ago
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