In short, and in general:
Advantages
<span>Credit Unions typically pay higher dividend rates on savingsCredit Unions typically offer lower rates on loansCredit Unions typically provide better service; since they are owned and governed by their membership, they tend to prioritize the needs of their members above all elseCredit Unions operate on a not-for-profit business model, so excess earnings are returned back to the membership in form of competitive rates and lower fees, and sometimes even special dividendsMany Credit Unions offer the same products and services found at banksCredit Unions often have added-value benefits, such as free financial education, discounted theme park tickets, and special member rates for services such as home alarm systems...even discounts at online retailers like Barnes & Noble.</span>Disadvantages
<span>Credit Unions, and in particular smaller local credit unions, struggle to match the level of convenience (ATMs and branches) that many banks provide their customers, although many CUs are part of shared networks which enhance the breadth of delivery channels available to their membersSome Credit Unions are limited in their product offeringsOne must qualify for membership <span>One must pay a membership fee to join. hope this helps!
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One is their traits and their characterists that they have in common
B is you answer sorry i dont quite know how to explain it in a way that you and anybody else would understand it.
Answer:
Mass of object is 0.5kg
Explanation:
Given the following data;
Force = 6N
Acceleration = 12m/s²
Mass =?
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
Where;
F represents force.
m represents the mass of an object.
a represents acceleration.
Making mass (m) the subject, we have;
Substituting into the equation;
Mass, m = 0.5kg.
Therefore, the mass of the object is 0.5kg
Answer:
D.
Explanation:
To solve the exercise it is necessary to apply the concepts related to the Magnetic Field described by Faraday.
The magnetic field is given by the equation:
Where,
Permeability constant
d = diameter
I = Current
For the given problem we have a change in the diameter, twice that of the initial experiment, therefore we define that:
The ratio of change between the two is given by:
Therefore the correct answer is D.
