A football is kicked straight up in the air , it hits the ground 5.6 s later. What was the greatest height kicked reached by the
2 answers:
You might be interested in
Answer : The correct option is, (d) 4 times
Solution :
According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.
Formula used :
where,
F = electrostatic force of attraction or repulsion
= Coulomb's constant
and
are the charges
r = distance between two charges
First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'
..........(1)
Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.
...........(2)
Equation equation 1 and 2, we get
Therefore, the force exerted between S and q is 4 times the force exerted between S and p.
Answer:
20.996 m
Explanation:
Given:
Initial velocity,
Final velocity,
Total time taken, s.
∴ Acceleration is given as,
m/s²
Now, using Newton's equation of motion, we find the displacement.
Displacement is given as:
Plug in 0 for , 4.91257 for
and 1.74 for
. Solve for
.
This gives,
Therefore, the train's displacement in the first 4.91257 s of motion is 20.996 m.