Answer:
first four terms are 2, 7, 12, 17
Step-by-step explanation:
use this formula: =
+ (n - 1)· d
where 'n' equals the position in the sequence the term is in and 'd' is the common difference
if = 2 and d = 5 are given, plug those into formula
= 2
= 2 + (2 - 1)·5 = 2+5 = 7
= 2 + (3 - 1)·5 = 2+2(5) = 12
= 2+(4 - 1)·5 = 2+3(5) = 17
Answer: The probability that a random selected bottle will have less than 440 ml of beer is 23.882% (0.23882)
find attached drawing of the area under the normal distribution and readings off the normal distribution table
Step-by-step explanation:
QUESTION: Beer bottles are filled so that they contain an average of 445 ml of beer in each bottle. Suppose that the amount of beer in a bottle is normally distributed with a standard deviation of 7 ml. a. What is the probability that a randomly selected bottle will have less than 440 ml of beer
ANSWER:
Taken the given data from the question,
mean = μ = 445 ml
standard deviation = σ = 7 ml
x= 440 ml
One would also need to illustrate the area covered by such a region in a normal distribution curve (Kindly find attached a diagram of this)
FIRST STEP Find the z-score
The distribution is a normal distribution, so the z-score is
z = (x-μ)/σ = (440 - 445)/7 = -0.71 (2 d.p)
SECOND STEP Finding the probability of the z-score from a normal distribution which is equivalent to the the probability we are looking for
Pr(x < 440 ml) = Pr (z < -0.71) = 0.23882 [THIS IS GOTTEN FROM THE STANDARD NORMAL DISTRIBUTION TABLE, kindly find attached a picture illustrating the way the solution is gotten from the table]
The standard normal distribution table takes the probability of areas to the left. Reading the table one should take the the value with -0.7 and the 0.01.
Therefore, the probability of a beer chosen at random to be less than 440 ml is 23.882% (leaving in percentage or 0.23882)
