<u>Part A</u>
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<u>Part B</u>
The vertex of the graph will be a maximum because the leading coefficient is negative.
The x coordinate of the vertex is
.
When x=15/8,
.
So, the vertex has coordinates 
<u>Part C</u>
Plot the two x-intercepts and the vertex and then draw a curve in the shape of a parabola passing through them.
The graph is in the attached image.
Answer:
(y^2+3y-28)/(4y^2-15y-4)
Step-by-step explanation:
(4y-1)(y-3)(2y+3)(y+3)(y+7)(y-3)/(2y+3)(y-4)(4y+1)(4y-1)(y-3)(y+3)
= (y+7)(y-3)/(y-4)(4y+1)
= (y^2+3y-28)/(4y^2-15y-4)
Answer:
I will answer the Question
Step-by-step explanation:
Let's begin by evaluating f(x) using the value of 3: f(x) = 2x2 - 4x - 4 (original function) f(3) = 2(3)2 - 4(3) - 4 (plugging in 3 for x) f(3) = 2 (computed result) Now let's evaluate g(x) using the value of 3: g(x) = 4x - 7 (original function) g(x) = 4(3) - 7 (plugging in 3 for x) g(x) = 5 (computed result) Finally, we'll sum our results: (f + g)(3) = 2 + 3 (add f(3) and g(3)) <span>(f + g)(3) = 5 (final answer)</span>