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4 years ago

In the following chemical reaction, what product is represented by X?

Chemistry

1 answer:

olasank [31]4 years ago

6 0

Answer:

Al (Aluminum)

Al (OH)₃

Explanation:

Reaction Given:

AlCl₃ + NaOH -------> X (OH)₃ + NaCl

As we see at the reactants there are to compounds combining together

that is Aluminum Chloride and Sodium hydroxide.

Reaction Reactant:

AlCl₃

NaOH

This reaction is type of double displacement.

Now

if we look at the product side we again have 2 types of products

Reaction Products

1. X(OH)₃

2. NaCl

So,

Also according to law of definite composition a chemical compound have fixed ratio of component in product.

So, If we look at both the reactant and product atoms in compounds only Aluminum (Al) is missing on the product side.

Also if we look at the product i.e. X(OH)₃ means that 3 OH groups are combine with an atom that have the tendency of combining with 3 OH group and have valency of 3.

So only aluminum have the 3+ valency and can form a compound with OH have 3 at its base in unit formula.

So,

The product will be

Al (OH)₃

And the balanced chemical reaction will be

AlCl₃ + 3NaOH -------> Al(OH)₃ + 3NaCl

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3 years ago

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4 years ago

Read 2 more answers

When hydrochloric acid is poured over potassium sulfide, 42.5 mL of hydrogen sulfide gas is produced at a pressure of 756 torr a

EastWind [94]

<h2>Answer:</h2> $0.1899grams$

<h2>Explanations:</h2>

The balanced chemical reaction between hydrochloric acid and potassium sulfide is as shown:

$K_2S+2HCl\to H_2S+2KCl$

Based on stoichiometry, we can see that 1 mole of potassium sulfide reacted to form 1 mole of hydrogen sulfide.

Get the mole of hydrogen sulfide gas (H2S) using the ideal gas equation expressed as:

$\begin{gathered} PV=\text{nRT} \\ n=\frac{PV}{RT} \end{gathered}$

P is the pressure of the gas (in atm) = 0.994737atm (756torr)

V is the volume of the gas = 42.5mL = 0.0425L

T is the temperature (in Kelvin) = 26 + 273 = 299K

R is the gas constant = 0.0821 L*atm/mole * K

Substitute these values into the formula as shown:

$\begin{gathered} n=\frac{0.994737\cancel{\text{atm}}\times0.0425\cancel{L}}{0.0821\frac{\cancel{L}\cdot\cancel{\text{atm}}}{\text{mole}\cdot\cancel{K}}\times299\cancel{K}} \\ n=\frac{0.994737\times0.0425}{0.0821\times299} \\ n=\frac{0.0422763225}{24.5479} \\ n=0.00172\text{moles} \end{gathered}$

Since the number of moles of hydrogen sulfide is 0.00172moles, the number of moles of potassium sulfide will also be 0.00172 moles (based on stoichiometry)

Get the mass of potassium sulfide that reacted using the formula:

$\text{Mass}=number\text{ of moles}\times molar\text{ mass}$

Number of moles of K2S = 0.00172 moles

Molar mass of K2S = 110.262 g/mol

Substitute into the formula for calculating the mass;

$\begin{gathered} \text{Mass}=0.00172\cancel{\text{moles}}\times\frac{110.262g}{\cancel{\text{mole}}} \\ \text{Mass}=0.1899\text{grams} \end{gathered}$

Therefore the mass of potassium sulfide that reacted (in grams) is approximately 0.1899grams

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1 year ago