Since it is in column 2A it would have an oxidation number of +2
Answer:
Lithium oxide, Li₂O.
Explanation:
Hello!
In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:
Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:
Thus, we perform the operations in order to obtain:
So we solve for x as shown below:
Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.
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Hello there!
The nuclear emanations 1, 2 and 3 are called, respectively:
1) Alpha, beta and gamma
Alpha Radiation consists of two protons and two neutrons, as protons are positive particles, they will be attracted to the negatively charged plate.
Beta Radiation is composed of a high-energy electron. As electrons are negative particles, they will be attracted to the positively charged plate.
Gamma Radiation is composed or photons. Photons don't have charge or mass, and they will not be attracted to the charged plates. This kind of radiation is more penetrating than the other two.
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5.732 grams of AgCl is formed when 0.200 L of 0.200 M AGNO3 reacts with an excess of CaCl2.
Explanation:
The balanced equation:
2 AgNO3(aq) + CaCl2(aq) -----> 2 AgCl(s) + Ca(NO3)2(aq)
data given:
volume of AgNO3 = 0.2 L
molarity of AgNO3 = 0.200 M
atomic weight of AgCl= 143.32 gram/mole
from the formula, number of moles can be calculated
Molarity = 
number of moles of AgNO3 = 0.04
From the reaction:
2 moles of AgNO3 reacts to form 2 moles of AgCl
0.04 moles of AgNO3 reacts to form x mole of AgCl
= 
= 0.04 moles of AgCl is formed
mass of AgCl formed is calculated by multiplying number of moles with atomic mass of AgCl
mass of AgCl = 0.04 x 143.32
= 5.732 grams of AgCl is formed.
Wow, now this one is a hard one, took me quite a while to figure it out but here it is:

The abundances of the two isotopes is:
Antimony-121 = 57.2%
Antimony-123 = 42.8%