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3 years ago

PLEASE HELP ME WITH PRE CAL!!

Mathematics

1 answer:

Oduvanchick [21]3 years ago

4 0

Answer:

0.67 mi

Step-by-step explanation:

The diagram illustrating the question is shown in the attach photo.

In triangle DCA,

Opposite = H

Adjacent = b

Angel θ = 27°

Tan θ = Opp /Adj

Tan 27° = H/b

Cross multiply

H = b x Tan 27°... (1)

From triangle DSA,

The diagram illustrating the question is shown in attach photo.

In triangle DCA,

Opposite = H

Adjacent = 2.3 – b

Angel θ = 34°

Tan θ = Opp /Adj

Tan 34° = H/ 2.3 – b

Cross multiply

H = Tan 34° (2.3 – b) .. (2)

Equating equation (1) and (2)

b x Tan 27° = Tan 34° (2.3 – b)

0.5095b = 0.6745(2.3 – b)

0.5095b = 1.55135 – 0.6745b

Collect like terms

0.5095b + 0.6745b = 1.55135

1.184b = 1.55135

Divide both side by 1.184

b = 1.55135/1.184

b = 1.31 mi

Substitute the value of b into any of the equation to obtain the height (H). In this case we shall use equation 1.

H = b x Tan 27°

H = 1.31 x Tan 27°

H = 0.67 mi

Therefore, the height of the drone is 0.67 mi

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