Answer:
122.735 behind converging lens ; 2.16
Explanation:
Given tgat:
Object distance, u = 29 cm
Image distance, v =
Focal length, f = - 19 (diverging lens)
Mirror formula :
1/u + 1/v = 1/f
1/29 + 1/v = - 1/19
1/v = - 1/19 - 1/29
1/v = −0.087114
v = −11.47916
v = -11.48
Second lens
Object distance :
u = 11.48 + 11 = 22.48 cm
1/v = 1/19 - 1/22.48
1/v = 0.0081475
v = 1 / 0.0081475
v = 122.735 cm
122.735 behind second lens
Magnification, m
m = m1 * m2
m = - v / u
Lens1 :
m1 = -11.48 / 29 = - 0.3958620
m2 = - 122.735 / 22.48 = - 5.4597419
Hence,
- 0.3958620 * - 5.4597419 = 2.16
Answer:
25N
Explanation:
100 - 75 = 25
That should be right if im not dumb...
The equation for calculating the Work is very simple that is Work=Force x Displacement. We have a Force given as 209N and displacement = 10 meter.
Putting these values directly in the formula gives us Work = 209N x 10m
Work = 2090 Joule.
The weight of the bricks is not needed hear.
Answer:
True
Explanation:
It is possible to reduce/lessen the force that is acting on an object. For example, if you were pushing on a box and wanted to push less on the box, that would be possible.
