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3 years ago

If the units of your answer are kg ∙ m2/s3, which of the following types of quantities could your answer be?

Physics

2 answers:

kirza4 [7]3 years ago

4 0

Answer:

D. power

Explanation:

kg represents mass

(m/v)² represents velocity squared

Then kg·m²/s² represents mass·velocity² = kinetic energy or potential energy or work.

kg·m²/s³ will be the rate of doing work, which is power

Harlamova29_29 [7]3 years ago

4 0

Answer:

D. Power

Explanation:

Power is defined as “time rate of change in energy”. So,

P = W/t

P = (kgm^2/s^2)/s

P = kgm^2/s^3

Now,

Units of potential Energy = units of kinetic energy = units of work = Fd = kgm^2/s^2

Units of force = F = ma = kgm/s^2

Hence,(D) Power is the right answer .

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A 1.25-kg ball begins rolling from rest with constant angular acceleration down a hill. If it takes 3.60 s for it to make the fi

miv72 [106K]

Answer:

The time taken is $\Delta t = 1.5 \ s$

Explanation:

From the question we are told that

The mass of the ball is $m = 1.25 \ kg$

The time taken to make the first complete revolution is t= 3.60 s

The displacement of the first complete revolution is $\theta = 1 rev = 2 \pi \ radian$

Generally the displacement for one complete revolution is mathematically represented as

$\theta = w_i t + \frac{1}{2} * \alpha * t^2$

Now given that the stone started from rest $w_i = 0 \ rad / s$

$2 \pi =0 + 0.5* \alpha *(3.60)^2$

$\alpha = 0.9698 \ s$

Now the displacement for two complete revolution is

$\theta_2 = 2 * 2\pi$

$\theta_2 = 4\pi$

Generally the displacement for two complete revolution is mathematically represented as

$4 \pi = 0 + 0.5 * 0.9698 * t^2$

=> $t^2 = 25.9187$

=> $t= 5.1 \ s$

The time taken to complete the next oscillation is mathematically evaluated as

$\Delta t = t_2 - t$

substituting values

$\Delta t = 5.1 - 3.60$

$\Delta t = 1.5 \ s$

7 0

3 years ago

3730 watts equals about how many horsepower A.5 B.10 C.20 D.30

ikadub [295]

3,730 W is equal to about 5 horsepower. (4.9982 hp)

4 0

3 years ago

Read 2 more answers

I am really struggling with this question because I can't find anything on aphelion and perihelion, it's not a topic we went ove

Hoochie [10]

I have a strange hunch that there's some more material or previous work
that goes along with this question, which you haven't included here.

I can't easily find the dates of Mercury's extremes, but here's some of the
other data you're looking for:

Distance at Aphelion (point in it's orbit that's farthest from the sun):
69,816,900 km
0. 466 697 AU

 Distance at Perihelion (point in it's orbit that's closest to the sun):
46,001,200 km
0.307 499 AU 

Perihelion and aphelion are always directly opposite each other in
the orbit, so the time between them is 1/2 of the orbital period.

Mercury's Orbital period = 87.9691 Earth days

1/2 (50%) of that is 43.9845 Earth days

The average of the aphelion and perihelion distances is

1/2 ( 69,816,900 + 46,001,200 ) = 57,909,050 km
or
1/2 ( 0.466697 + 0.307499) = 0.387 098 AU

This also happens to be 1/2 of the major axis of the elliptical orbit.

3 0

4 years ago

A scientist is trying to predict the regions of the world most likely to see a decrease in natural resources from population cha

aleksley [76]

Developed countries will see a decrease in natural resources, because their population will decrease.

8 0

3 years ago

Read 2 more answers

a surface recieving sound is moved from it original position to a position three times farther away from the source of the sound

Delicious77 [7]

Sound intensity = 1/(r^2)

That is Sound intensity is indirectly proportional to the distance. Therefore, sound becomes 9 times less intense.

7 0

3 years ago