The electric output of the plant is 48.19 MW
First we need to calculate the water power, it is given by the formula
WP=ρQgh
Here, ρ=1000 kg/m3 is density of water,Q is the flow rate, g is the gravity, and h is the water head
Therefore, WP=1000*65*9.81*90=57388500 W=57.38 MW
Now the overall efficiency of the hydroelectric power plant is given as
η=
Plugging the values in the above equation
0.84=EP/57.38
EP=48.19 MW
Therefore, the electric output of the plant is 48.19 MW.
Is this about using triangular prisms in spectrometer experiments ? See enclosed
Answer:
a bowling ball because its heavier
Explanation:
<span>The given statement is True,as the generated voltage is stepped up for transmission.Hence,</span><span>The voltage of the electric current produced by a generating plant is lower than the voltage of the current carried by transmission lines.</span>
Answer A: When their separation increases.
Hope this helps! :D