A person sits at rest on a chair. The gravitational force on the person (their weight) is one half of an action-reaction pair. W
1 answer:
You might be interested in
Answer:
c. V = 2 m/s
Explanation:
Using the conservation of energy:
so:
Mgh =
where M is the mass, g the gravity, h the altitude, I the moment of inertia of the pulley, W the angular velocity of the pulley and V the velocity of the mass.
Also we know that:
V = WR
Where R is the radius of the disk, so:
W = V/R
Also, the moment of inertia of the disk is equal to:
I =
I =
I = 10 kg*m^2
so, we can write the initial equation as:
Mgh =
Replacing the data:
(5kg)(9.8)(0.3m) =
solving for V:
(5kg)(9.8)(0.3m) =
V = 2 m/s
Answer:
(a). The reactive power is 799.99 KVAR.
(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.
Explanation:
Given that,
Power factor = 0.6
Power = 600 kVA
(a). We need to calculate the reactive power
Using formula of reactive power
...(I)
We need to calculate the
Using formula of
Put the value into the formula
Put the value of Φ in equation (I)
(b). We draw the power triangle
(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95
Using formula of reactive power
We need to calculate the difference between Q and Q'
Put the value into the formula
Hence, (a). The reactive power is 799.99 KVAR.
(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.
