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cestrela7 [59]
2 years ago
12

A person sits at rest on a chair. The gravitational force on the person (their weight) is one half of an action-reaction pair. W

hich force is the other half?
Physics
1 answer:
Feliz [49]2 years ago
7 0

Normal is the  other half of an action-reaction pair

If a person is sitting on a chair , there must be a gravitation force acting in downward direction which is equal to the weight of that person . That means the person is exerting a force on the chair equal to its weight . But the person is not falling down the chair , because of newtons third law of motion .

There must be a counter force which is equal and opposite to the force exerted by the person on the chair , in order to make net force equal to zero and to make that man in stationary state ( no movement )  .That force is called Normal force which is been acted by the chair on the person .This implies Normal is the  other half of an action-reaction pair

learn more about Force:

brainly.com/question/14110395?referrer=searchResults

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A uniform solid sphere of radius r = 0.510 m and mass m = 15.5 kg turns counterclockwise about a vertical axis through its cente
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5.160384 kg*m²/s

Explanation:

The vector angular momentum P can be found using the following expression:

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I refers to the inertia, that for a sphere is found using the expression:

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a boy pulls 23 kg box with a 100 N force at 39 above a horizontal surface if the coefficient of kinetic friciton between the box
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Answer:

Total work done is 2606.08 J.

Explanation:

Given :

Mass of box , m = 23 kg .

Force applied , F = 100 N .

Angle from horizon , \theta=39^o.

Coefficient of kinetic friction , \mu=0.16.

Distance travelled by box , d = 34 m .

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Total work done = work done by boy + work done by friction.

W=Fdcos\theta+f_sdcos\theta=Fd-\mu(mg) \\\\W=100\times cos39^o\times 34-0.16\times 23 \times 9.8 \\\\W=77.71\times 34-36.06=2606.08\ J.

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