Answer:
A. 50.24
Step-by-step explanation:
<em><u>It is given that "r," represents the radius, and it's also given that it's 4. All you need to do is plug in 4 for r, into the function, like so:</u></em>
<em><u /></em>![f(4) = 3.14(4)^2](https://tex.z-dn.net/?f=f%284%29%20%3D%203.14%284%29%5E2)
f(4) = 3.14(16)
f(4) = 50. 24
4x - 2y = 14
y = 0.5x -1
Get just one variable on one side for both equations.
4x - 2y = 14 ⇒ 4x = 2y + 14 ⇒ 4x - 14 = 2y
y = 0.5x - 1 ⇒ x - 2 = 2y
Use the transitive property and then solve for x.
x-2 = 4x-14
12 = 3x
x = 4
<em>Edit: Apprently I didn't use substitution. Oops! Sorry...</em>
Hello ,
there are 12 combinations
num x y z
1 0 1 2
2 0 3 1
3 0 5 0
4 5 0 2
5 5 2 1
6 5 4 0
7 10 1 1
8 10 3 0
9 15 0 1
10 15 2 0
11 20 1 0
12 25 0 0
DIM x AS INTEGER, y AS INTEGER, z AS INTEGER, k AS INTEGER
'OPEN "c:\nosdevoirs\monnaie.sol" FOR OUTPUT AS #1
k = 0
FOR x = 0 TO 25
FOR y = 0 TO 5
FOR z = 0 TO 3
IF x + 5 * y + 10 * z = 25 THEN
k = k + 1
PRINT k, x, y, z
' PRINT #1, k, x, y, z
END IF
NEXT z
NEXT y
NEXT x
'CLOSE #1
END
The answer to the question is 18.75
Answer:
30
Step-by-step explanation:
The 3 in "513" is only 3. it's 1, 2, 3. If we do 3 x 10 it's 30.
3 x 10 = 30.
"times greater" means multiplication if you were confused about it.
<u>Hope this helps! Have a nice day!</u>