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olga_2 [115]
2 years ago
10

PLEASE HELP

Mathematics
2 answers:
notka56 [123]2 years ago
7 0
You have to provide a picture so we can answer your question
leva [86]2 years ago
3 0

Answer:

I dont see a picture-

Step-by-step explanation:

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Based on the graph how many real number solutions to the equation X^3+6x^2+12x+8=0have
Igoryamba

ANSWER

One real root.

EXPLANATION

The graph of the function

f(x) =  {x}^{3}  +  6{x}^{2}  + 12x + 8

is shown in the attachment.

According to the Fundamental Theorem of Algebra, this function must have 3 roots including real and complex roots.

The x-intercepts gives the number of real roots.

Observe that the graph has only one intercept.

This implies that, the equation:

{x}^{3}  +  6{x}^{2}  + 12x + 8 = 0

has only one real solution.

7 0
3 years ago
What is the relative minimum of f(x)= -x2-4x+6
matrenka [14]

Answer:

(−2,10)

Step-by-step explanation:

hope this helps

3 0
3 years ago
A ship sails on a bearing of 020° for 30 km.
zepelin [54]

Answer:

The ship travels approximately 10.261 meters to the East.

Step-by-step explanation:

At first we introduce a graphical description of the statement as an attachment below. Let suppose that bearing is respect to the North-direction, then the change in position in the East direction is modelled by the following Trigonometric formula:

x = r\cdot \sin \theta (1)

Where:

r - Distance travelled by the ship, measured in kilometers.

\theta - Bearing angle, measured in sexagesimal degrees.

x - Distance component in the east direction, measured in kilometers.

If we know that r = 30\,km and \theta = 20^{\circ}, then the distance in the East direction is:

x = (30\,km)\cdot \sin 20^{\circ}

x \approx 10.261\,m

The ship travels approximately 10.261 meters to the East.

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3 years ago
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5 0
2 years ago
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