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3 years ago

Use proportion to find the whole 75 is 15% of what number

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

7 0

Answer:

Your answer would be 11.25

Step-by-step explanation:

(is) = part = %

(of) = whole = 100%

x/75 = 15/100

x = 11.25

(ps i looked up how to do this so correct me if i'm wrong. Thanks!)

Iteru [2.4K]3 years ago

3 0

Answer:

500

Step-by-step explanation:

15% * x = 75

(15/100) * x = 75 Multiply both sides by 100/15

(15/100)*(100/15) = 75 * 100/15

x = 7500/15

x = 500

Answer 500

Proportion

15/100 = 75 / x Cross multiply

15x = 100*75 Combine the right

15x = 7500 Divide 15

15x/15 = 7500/15

x = 500

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The equation x+53=15 can be solved by performing two operations on both sides.

Wewaii [24]

Hey!

You're right! This equation can definitely be solved by performing two operations on both sides. Let me show you how it's done.

First, let's write out our equation.

Original Equation :
x + 53 = 15

Now that that's done, we'll be performing two operations on both sides. The operation we'll want to do is subtracting both sides of the equation by 53. We do this to get x on its own.

Original Equation :
x + 53 = 15

New Equation {Added Subtract 53 to Both Sides} :
x + 53 - 53 = 15 - 53

Now we have to solve the equation. Let's do the left side first.

Left Side of the Equation :
x + 53 - 53

Left Side of the Equation {Solved} :
x

Now, we'll solve the right side of the equation.

Right Side of the Equation :
15 - 53

Right Side of the Equation {Solved} :
-38

Now we can put both solutions to both sides of the equation together.

New Equation :
x = -38

Since this cannot be simplified any farther, this is our final answer. And that's it!

So, now we know that in the equation x + 53 = 15, x = -38

Hope this helps!

- Lindsey Frazier ♥

3 0

3 years ago

I need help please it would really help

Softa [21]

Answer:

Step-by-step explanation:

V = 4/3 * radius^3 * pi = 4/3 * 4^3 * pi = 256 /3 * pi

7 0

3 years ago

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$