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Sunny_sXe [5.5K]
2 years ago
13

Simultaneous linear equations

Mathematics
1 answer:
Talja [164]2 years ago
8 0
<span>1) 3x + y = 23
6x + y = 44

Subtract 1st from 2nd, 
3x = 21
x = 7
Then, y = 23 - 3(7) = 2

In short, Your Answer would be: (7, 2)

2) </span><span>4x - 3y = 21
2x + 3y = 33

Add the equations, 
6x = 54
x = 9
Then, 2(9) + 3y = 33
3y = 33 - 18
y = 15/3
y = 5

In short, Your Answer would be: (9, 5)

3) </span><span>5x + 2y = 13
6y + 5x = 29
Subtract 1st from 2nd equation, 

4y = 16
y = 4
Then, 5x  = 13 - 2(4)
x = 5/5 = 1

In short, Your Answer would be: (1, 4)

4)  </span><span>5x - 4y = 2
10x - 4y = 32
Subtract 1st from 2nd equation, 
5x = 30
x = 6

Then, 5(6) - 2 = 4y
y = 28/4 = 7

In short, Your Answer would be: (6, 7)

5) </span><span>2x + 7y = 48
x + 3y = 21

Here, x = 21-3y
Substitute in in 1st equation, 
2(21-3y) + 7y = 48
42 - 6y + 7y = 48
y = 6

Then, x = 21 - 3(6) = 3

In short, Your Answer would be: (3, 6)

6) </span><span>8x - 3y = 44
2y - 4x = -20

Multiply 2nd equation by 2 
-8x + 4y = -40
Now, add it to 1st equation, 
y = 4

Then, 2(4) - 4x = -20
4x = 8 + 20
x = 28/4 = 7

In short, Your Answer would be: (7, 4)

Hope this helps!</span>
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The debt-to-credit ratio of a credit account is the ratio of the balance to the credit limit:

... balance/credit limit = 245.78/3500 = 0.07022... ≈ 7.02%

The appropriate choice is ...

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7 0
3 years ago
A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard
Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

\sigma=\frac{0.8}{\sqrt{37}}=0.13

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, P(z > 1.69) = 1 - P(z < 1.69)

P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0
3 years ago
Put 2/3 5/7 16/21 in order from least to greatest
hodyreva [135]

Answer:

5/7, 2/3, and 16/21

Step-by-step explanation:

If you put them all under the same denominator you will get 2/3=14/21, 5/7= 10/21, and 16/21. And if you put them in order it is 10/21, 14/21, and 16/21. Hope this helps, let me know if correct!!

5 0
3 years ago
Read 2 more answers
Evaluate x/y + 5 w^2, for x = 2/3 and y = 5/6, and w = 3
tresset_1 [31]
2/3 / 5/6 + 5 (3)^2

= 2/3 * 6/5 + 45

= 12/15 + 45  

= 45 4/5  Answer
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Danny wants to put a circular fence in his backyard. He measured from the center of his space and got 12 how much fencing does d
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Answer: 75.4

Steps:
Circumference = 2πr
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r = radius

2π(12) = 75.39822
3 0
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