Answer: PC servers
Explanation: PC(Personal computer) servers are the helps in the utilization of the network services to the software and hardware of the computer. It manages the network resources . In the past time ,Mindrange computers, mini computers etc are present time's PC servers.
Other options are incorrect because laptops ,PDA(Personal digital assistant) or tablets are the modern version of the computer units that are portable and compact with fast processing. Thus the correct option is option PC servers.
Over the last decade, the overall energy consumption of cloud data centers worldwide has remained relatively the same because the technology supporting cloud data centers has become much more energy efficient.
<h3>Why has the energy consumption of cloud data centers remained the same?</h3>
The reason is that servers are said to be six times as heavy as data in terms of energy consumption is one that is seen to be due to improved hardware efficiency.
In regards to cloud, the machines are said to be running by giving web services and other machines room to consumes some level or amount of energy that can be used for working.
Hence, Over the last decade, the overall energy consumption of cloud data centers worldwide has remained relatively the same because the technology supporting cloud data centers has become much more energy efficient.
Learn more about cloud data centers from
brainly.com/question/13440433
#SPJ1
See full question below
Over the last decade, the overall energy consumption of cloud data centers worldwide has remained relatively the same. Why is this so? The technology supporting cloud data centers has become much more energy efficient. There is significantly less customer demand for cloud computing than a decade ago. Cloud providers have placed limits on the amount of data stored at each center. Cloud data centers operate with less computing power than they did in the past.
The answer is sort key. A Sort Key is the column of data in a database that is used as the basis for arranging data. Iy is also used for rearranging data in the column. An Operational Database is used to collect, modify, and maintain data on a daily basis.
Answer:(1) To manage the computer's resources, which includes central processing unit, memory, disk drives, and printers, (2) To establish a user interface
(3)To execute and provide services for applications software.
The old mainframe computers have
(1) low memory sizes
(2) slower connectivity speed
(3) Larger sizer
(4) low sophistication.
Explanation: Operating system is a system software that manages the computer resources,helps to establish user interface and it helps to provide services for application softwares.
Operating system software includes WINDOWS X,WINDOWS 7,WINDOWS 8,LINUX,etc.
Mainframe computers are computers used by large multinational companies for processing bulk data. Old mainframe computers were produced by IBM(INTERNATIONAL BUSINESS MACHINE) in the year 1952 they are classed two scientific and commercial mainframe computers with different information although they had some incompatibilities. Old mainframe computers are large in size with low processing speed, sophistication and storage compared to present day system.
Answer:
C++ code explained below
Explanation:
#include<bits/stdc++.h>
#include <iostream>
using namespace std;
int FiboNR(int n)
{
int max=n+1;
int F[max];
F[0]=0;F[1]=1;
for(int i=2;i<=n;i++)
{
F[i]=F[i-1]+F[i-2];
}
return (F[n]);
}
int FiboR(int n)
{
if(n==0||n==1)
return n;
else
return (FiboR(n-1)+FiboR(n-2));
}
int main()
{
long long int i,f;
double t1,t2;
int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};
cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;
cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;
for(i=0;i<16;i++)
{
clock_t begin = clock();
f=FiboR(n[i]);
clock_t end = clock();
t1=double(end-begin); // elapsed time in milli secons
begin = clock();
f=FiboNR(n[i]);
end = clock();
t2=double(end-begin);
cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds
}
return 0;
}