The total value is:
5. 5 x 10 ^5 * 23 x 10^3 =
= $126.5 * 10^8 =
= $1.265 x 10^10
Answer: B )
Multiplication is the process of multiplying. The total number of cupcakes that are produced by the 3 girls is 44.
<h3>What is multiplication?</h3>
Multiplication is the process of multiplying, therefore, adding a number to itself for the number of times stated. For example, 3 × 4 means 3 is added to itself 4 times, and vice versa for the other number.
Given that Tammy baked a batch of 20 cupcakes and Daniella baked 4/5 as many cupcakes as Tammy. Therefore, the number of cupcakes made by Daniella is,
Number of cupcakes made by Daniella
= (4/5)×(Number of cupcakes made by Tammy)
= (4/5) × 20
= 16
Now, if Miko baked 1/2 as many cupcakes as Daniella. Therefore, the number of cupcakes made by Miko is,
Number of cupcakes made by Miko
= (1/2) × (Number of cupcakes made by Daniella)
= (1/2) × 16
= 8
Further, the total number of cupcakes that are produced are,
Number of cupcakes = 20 + 16 + 8 = 44
Hence, the total number of cupcakes that are produced by the 3 girls is 44.
Learn more about Multiplication here:
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To find the correct function, just plug in 10 and 2 to see if the function equals zero with both numbers.
f(x)=x^2-12x+20
f(10)=100-120+20
f(10)=0 --> that's what we want, so let's check the other number
f(x)=x^2-12x+20
f(2)=4-24+20
f(2)=0 --> perfect. this function has zeros at both x=10 and x=2
The function that has zeros at both x=10 and x=2 is f(x)=x^2-12x+20.
Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,
(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.
