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3 years ago

For a constant force the impulse could be increased by

Physics

2 answers:

Aleksandr [31]3 years ago

5 0

For constant fore the impulse could be increased by increasing the time for the force.

Klio2033 [76]3 years ago

3 0

F (delta) T = impulse
If the force is constant, the time has to increase in order for the impulse to increase

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A woman with a mass of 52.0 kg is standing on the rim of a large disk that is rotating at an angular velocity of 0.470 rev/s abo

Charra [1.4K]

Explanation:

It is given that,

Mass of the woman, m₁ = 52 kg

Angular velocity, $\omega=0.47\ rev/s=2.95\ rad/s$

Mass of disk, m₂ = 118 kg

Radius of the disk, r = 3.9 m

The moment of inertia of woman which is standing at the rim of a large disk is :

$I={m_1r^2}$

$I={52\times 3.9^2}$

I₁ = 790.92 kg-m²

The moment of inertia of of the disk about an axis through its center is given by :

$I_2=\dfrac{m_2r^2}{2}$

$I_2=\dfrac{118\times (3.9)^2}{2}$

I₂ =897.39 kg-m²

Total moment of inertia of the system is given by :

$I=I_1+I_2$

$I=790.92+897.39$

I = 1688.31 kg-m²

The angular momentum of the system is :

$L=I\times \omega$

$L=1688.31 \times 2.95$

$L=4980.5\ kg-m^2/s$

So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.

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3 years ago

In which of these situations is convection most likely the main form of heat transfer? A.Warm air from a heater on the first flo

Sergeeva-Olga [200]

All points ate true

But option A is perfect

6 0

3 years ago

Read 2 more answers

Stars set about how many minutes earlier each day? A. 8 B. 6 C. 4 D. 2

Furkat [3]

It is c which is four minutes per day

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3 years ago

The mass of M1 = 12 Daltons and it has a speed of v1 = 200 m/s. The mass of M2 = 4 Daltons. What was the total momentum of the s

svet-max [94.6K]

Answer:

The total momentum is $p__{T }} =(2400 -4 v_2) \ Dalton \cdot m/s$

Explanation:

The diagram illustration this system is shown on the first uploaded image (From physics animation)

From the question we are told that

The mass of the first object is $M_1 = 12 \ Dalton$

The speed of the first mass is $v_1 = 200 \ m/s$

The mass of the second object is $M_2 = 4 \ Dalton$

The speed of the second object is assumed to be $- v_2$

The total momentum of the system is the combined momentum of both object which is mathematically represented as

$p__{T }} = M_1 v_1 + M_2 v_2$

substituting values

$p__{T }} = 12 * 200 + 4 * (-v_2)$

$p__{T }} =(2400 -4 v_2) \ Dalton \cdot m/s$

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3 years ago

In a house 5 bulbs of 25 watts each are used for 6 hours a day.Calculate the unit of electricity consumed in a month of 30 days.

Svetradugi [14.3K]

(5 bulbs) x (25 watt/bulb) x (6 hour/day) x (30 day/month) =

 (5 x 25 x 6 x 30) watt-hour/month =

 22,500 watt-hour/month .

The most common unit of electrical energy used for billing purposes
is the 'kilowatt-hour' = 1,000 watt-hours .

 22,500 watt-hour/month = 22.5 kWh/month.

 (22.5 kWh/month) x (1.50 Rs/kWh) = 33.75 Rs / month

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3 years ago