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jeka94
3 years ago
8

6. A car accelerates from rest to 5m/s in 20 s. The force from the engine is 2000N. The force of air resistance and friction act

ing is 1000N. What is the cars mass?
Physics
1 answer:
otez555 [7]3 years ago
4 0

Answer:

net force= 2000-1000=1000

a=v-u/t=5/20=1/4

m=?

m=f/a

=1000÷1/4=4000kg

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As the shuttle bus comes to a sudden stop to avoid hitting a dog, it accelerates uniformly at -4.1 m/s^2 as it slows from 9.0 m/
zhuklara [117]

Acceleration  =  (change in speed) / (time for the change)

      - 4.1 m/s²  =  (-9 m/s)  /  (time for the change)

Time for the change  =  (-9 m/s) / (-4.1 m/s²)  =   2.2 seconds
3 0
3 years ago
Which item could you use in place of an ammeter to demonstrate that a
love history [14]

Answer:

the answer is D

Explanation:

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2 years ago
Which among the following statement/s is correct?
seropon [69]

Answer:

(D) None

Explanation:

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Examples of this force at work are;

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  • The force that causes a rock to roll downside a hill
  • The force causing people to walk on the earth surface instead of floating

The force that facilitates a pen on your hand to write on a paper is friction force between the pen and the paper. Gravitational force acts downwards thus force applied on an object beside you is not the force of gravity.

8 0
2 years ago
Mike is standing on the roof of a building looking at the roof of the neighboring building that is 15 meters away and 10 meters
amid [387]

Answer:

Part a)

t = 1.65 s

Part b)

x = 40.4 m

Since the distance of other building is 15 m so YES it can make it to other building

Part c)

v = 27.3 m/s

direction of velocity is given as

[tex]\theta = 26.35 degree

Explanation:

Part a)

acceleration due to gravity on this planet is 3/4 times the gravity on earth

So the acceleration due to gravity on this new planet is given as

a = \frac{3}{4}(9.81)

a = 7.36 m/s^2

now the vertical displacement covered by the canister is given as

y = 10 m

now by kinematics we have

y = \frac{1}{2}gt^2

10 = \frac{1}{2}(7.36)t^2

t = 1.65 s

Part b)

Horizontal speed of the canister is given as

v_x = 24.5 m/s

now the distance moved by it

x = v_x t

x = 24.5 (1.65)

x = 40.4 m

Since the distance of other building is 15 m so YES it can make it to other building

Part c)

Final velocity in X direction will remains the same

v_x = 24.5 m/s

final velocity in Y direction

v_y = v_i + at

v_y = 0 + (7.36)(1.65)

v_y = 12.14 m/s

now magnitude of velocity is given as

v = \sqrt{v_x^2 + v_y^2}

v = \sqrt{24.5^2 + 12.14^2}

v = 27.3 m/s

direction of velocity is given as

\theta = tan^{-1}\frac{v_y}{v_x}

\theta = tan^{-1}\frac{12.14}{24.5}

[tex]\theta = 26.35 degree

6 0
2 years ago
A jet accelerates at a=3.92 m/s2 from rest until it reaches its takeoff velocity of 360 km/hr. It has to travel for 5 seconds at
Art [367]

Answer:

\Delta s = 1775.510\,m

Explanation:

The minimum distance for takeoff is:

\Delta s = \Delta s_{1} + \Delta s_{2}

\Delta s = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a} + v_{f}\cdot \Delta t

\Delta s = \frac{(100\,\frac{m}{s} )^{2}-(0\,\frac{m}{s} )^{2}}{2\cdot (3.92\,\frac{m}{s^{2}})}+(100\,\frac{m}{s} )\cdot (5\,s)

\Delta s = 1775.510\,m

7 0
2 years ago
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