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Tems11 [23]
3 years ago
13

Which is true?The photoelectric effect occurs only for frequencies below the cutoff frequency, regardless of the intensity.The p

hotoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.The photoelectric effect occurs only for frequencies below the cutoff frequency and only for intensities above a cutoff intensity.The photoelectric effect occurs only for frequencies above the cutoff frequency and only for intensities above a cutoff intensity.
Physics
2 answers:
Crank3 years ago
7 0

Answer:

The photoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.

Explanation:

The photoelectric effect occurs when light is shined on metals such as zinc beyond a certain frequency (the threshold frequency), which causes electrons to escape from the zinc. The electrons which are fleeing are called photo electrons.

Therefore photo electric effect is

The photoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.

SIZIF [17.4K]3 years ago
6 0

Answer:

Explanation:

When a photon of suitable frequency falls on the metal surface, the electrons are ejected from the surface. This minimum frequency required to jest eject the electrons from the metal surface is called cut off frequency.

So, the photoelectric effect occurs only for the frequencies above the cut off frequency regardless of the intensity of photons falling on the metal surface.

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A police car is at rest parallel to the highway and measures the speed of cars. It sends the signal with a frequency of 1200 Hz,
masha68 [24]

Answer:

a) The car was moving at a speed of 29.167\ m.s^{-1}

b) The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c) f_o=1283.33\ Hz

Explanation:

Given:

  • original frequency of the source, f=1200\ Hz
  • speed of the source, v_s=0\ m.s^{-1}
  • velocity of the obstacle car be, v_o
  • speed of sound, s=350\ m.s^{-1}
  • observed frequency, f_o=1100\ Hz

<u>Using the equation from the Doppler's effect:</u>

\frac{f_o}{f} =\frac{(s+v_o)}{(s-v_s)}

\frac{1100}{1200} =\frac{(350+v_o)}{350-0}

v_o=-29.167\ m.s^{-1}

a)

The car was moving at a speed of 29.167\ m.s^{-1}

b)

The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c)

Now when, v_s=50\ m.s^{-1}

Then, f_o=?

Using the Doppler's eq.:

\frac{f_o}{1200} =\frac{(350+(-29.167))}{(350-50)}

f_o=1283.33\ Hz

3 0
3 years ago
20 kg object travels 28 meter and stops. coefficient friction= 0.085 how much work was done by friction?
Tresset [83]
Assuming it is on a horizontal surface:
friction = μR
R = 20g (g is gravity 9.81)
so Friction = 0.085 x 20g
Work done is force x distance 
so Work done = 0.085 x 20g x 28
 = 466.956 J

7 0
4 years ago
A 9.76-m ladder with a mass of 22.6 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upw
galben [10]

Answer:

Part a)

\tau_{net} = 1397.1 Nm

Part b)

I = 702.06 kg m^2

Explanation:

Part a)

Torque on the rod is due to two forces

(i) Due to weight of the rod at mid point

(ii) Due to external force applied at the end

Now we have

\tau_{net} = FL - mg\frac{L}{2}

\tau_{net} = 254(9.76) - (22.6)(9.81)(\frac{9.76}{2})

\tau_{net} = 1397.1 Nm

Part b)

As per Newton's law we know that

\tau = I\alpha

now we have

1397.1 Nm = I(1.99 rad/s^2)

I = 702.06 kg m^2

6 0
4 years ago
Differences in ocean-surface height can be measured by _____.\
bonufazy [111]
<h3><u>Answer;</u></h3>

Satellite

Differences in ocean-surface height can be measured by<u> Satellite</u>

<h3><u>Explanation;</u></h3>
  • The topography of the ocean or the height of the ocean surface relative to a level of no motion provides the information on tides, and the distribution of heat and mass in the Earths's oceans.
  • <em><u>The ocean topography is measured using satellites altimeter. Satellites use radar altimeters that are specially made to measure the height of the ocean surface.  The satellites measure the height of the ocean surface with an accuracy of 3 cm relative to the center of the earth.</u></em>
  • Satellite altimeter combines precise orbit determination with accurate ranging by a microwave altimeter of ocean distance to the satellite.
3 0
3 years ago
Read 2 more answers
suppose a scientist found a new matal-like substance in the desert. He determined its mass to be 20 grams. The volume was determ
lys-0071 [83]

Density = (mass) / (volume)

Density = (20 g) / (5 cm³)

<em>Density = 4 g/cm³</em> .

The density of the substance is greater than the density of water. A lump of the substance <em>will sink in water</em>, <u>unless</u> the lump is formed into a shape that displaces 20 cm³ of water or more, such as a tiny boat shape.

6 0
3 years ago
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