1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tems11 [23]
3 years ago
13

Which is true?The photoelectric effect occurs only for frequencies below the cutoff frequency, regardless of the intensity.The p

hotoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.The photoelectric effect occurs only for frequencies below the cutoff frequency and only for intensities above a cutoff intensity.The photoelectric effect occurs only for frequencies above the cutoff frequency and only for intensities above a cutoff intensity.
Physics
2 answers:
Crank3 years ago
7 0

Answer:

The photoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.

Explanation:

The photoelectric effect occurs when light is shined on metals such as zinc beyond a certain frequency (the threshold frequency), which causes electrons to escape from the zinc. The electrons which are fleeing are called photo electrons.

Therefore photo electric effect is

The photoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.

SIZIF [17.4K]3 years ago
6 0

Answer:

Explanation:

When a photon of suitable frequency falls on the metal surface, the electrons are ejected from the surface. This minimum frequency required to jest eject the electrons from the metal surface is called cut off frequency.

So, the photoelectric effect occurs only for the frequencies above the cut off frequency regardless of the intensity of photons falling on the metal surface.

You might be interested in
A 438 gram ball is traveling east at 39 m/s when it is hit by a 2.4 kg softball bat. After being in contact with the bat for 302
leonid [27]

Answer:

The magnitude of the impulse vector of the bat is 29.346 kg.m/s

The direction of the impulse vector of the bat is in the initial direction of the ball before impact

Explanation:

The given parameters are;

The mass of the ball, m₁ = 438 g

The speed of the ball = 39 m/s

The mass of the softball bat = 2.4 kg

The time of contact = 302 ms = 0.302 seconds

The speed of rebound = 28 m/s

The impulse = The change in momentum = Δp = F × Δt = m × Δv

The impulse on the ball = m₁ × Δv = 0.438 × (39 - (-28)) = 29.346 kg·m/s

Given that force of reaction of the bat is in opposite direction but equal to the force of the ball, and the time and the duration of contact with the ball is the same for both the ball and the bat, the impulse vector ore equal and opposite

Therefore, the magnitude of the impulse vector of the bat = 29.346 kg.m/s

The direction of the impulse vector of the bat = The initial direction of the ball before impact.

7 0
3 years ago
A fish (6 kg) is being yanked vertically upward out of the water and the fishing line breaks. If the line is rated to a maximum
ANEK [815]

Answer:

15.2 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity. The S.I unit of acceleration is m/s²

From the question,

F-W = ma......................... Equation 1

Where F = Tension on the line, W = weight of the fish, m = mass of the fish, a = acceleration of the fish.

But,

W = mg........................ Equation 2

Where g = acceleration due to gravity.

Substitute equation 2 into equation 1

F-mg = ma

make a the subject of the equation

a = (F-mg)/m.................... Equation 3

Given: F = 150 N, m = 6 kg,

Constant: g = 9.8 m/s²

Substitute into equation 2

a = [150-(6×9.8)]/6

a = (150-58.8)/6

a = 91.2/6

a = 15.2 m/s²

Hence the minimum acceleration of the fish = 15.2 m/s²

4 0
3 years ago
A string is strung horizontally with a fixed tension. A wave of frequency 90 Hz is sent along the string, and it has a wave spee
ankoles [38]

Answer:

wave speed of the second wave 55.1 m/s

Explanation:

The wave speed of the second wave will going to be same i.e 55.1 m/s. As speed of wave is dependent on the medium and here in this case medium is remain same for second wave also i.e string only, no change in the medium noticed, therefore speed of second wave still remain same i.e 55.1 m/s.

6 0
3 years ago
Which chemical equation is balanced?
scoundrel [369]
The 4na + 02 —> wna20
6 0
3 years ago
A car travels a distance of 60 km in 2 hours. what is its speed in kilometers per hour?
White raven [17]

Answer:

30 kilometers per hour.

Explanation:

we know this by dividing 60 by 2

5 0
3 years ago
Other questions:
  • What is the definition of kinetic energy and potentail energy?
    6·2 answers
  • 2. A 14.8-kg child sits in a 1.30-kg swing. You pull the swing back, lifting it 52.1 cm vertically, and then let go. Determine t
    14·1 answer
  • In the chemical reaction in which carbon, hydrogen and oxygen absorb heat and combine to form carbon dioxide and water which of
    13·2 answers
  • Normal human body temperature is about 37°C. What is this temperature in kelvins? What is the peak wavelength emitted by a perso
    9·1 answer
  • Mr. Nakamora wants to test the accuracy of an old balance in his classroom compared to a brand-new balance that he knows is accu
    14·2 answers
  • A wheel, starting from rest, rotates with a constant angular acceleration of 2.80 rad/s2. During a certain 5.00 s interval, it t
    14·2 answers
  • Assume that in interstellar space the distance between two electrons is about 0.8 cm. The electric force between the two electro
    8·1 answer
  • The crane is used to support the engine, which has a weight of 1200 lb. Draw the shear and moment diagrams of the boom ABC when
    15·1 answer
  • A roller coaster, traveling with an initial speed of 23 m/s, decelerates
    11·1 answer
  • Why is the following situation impossible? An inquisitive physics student takes a 100-W lightbulb out of its socket and measures
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!