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Tems11 [23]
2 years ago
13

Which is true?The photoelectric effect occurs only for frequencies below the cutoff frequency, regardless of the intensity.The p

hotoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.The photoelectric effect occurs only for frequencies below the cutoff frequency and only for intensities above a cutoff intensity.The photoelectric effect occurs only for frequencies above the cutoff frequency and only for intensities above a cutoff intensity.
Physics
2 answers:
Crank2 years ago
7 0

Answer:

The photoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.

Explanation:

The photoelectric effect occurs when light is shined on metals such as zinc beyond a certain frequency (the threshold frequency), which causes electrons to escape from the zinc. The electrons which are fleeing are called photo electrons.

Therefore photo electric effect is

The photoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.

SIZIF [17.4K]2 years ago
6 0

Answer:

Explanation:

When a photon of suitable frequency falls on the metal surface, the electrons are ejected from the surface. This minimum frequency required to jest eject the electrons from the metal surface is called cut off frequency.

So, the photoelectric effect occurs only for the frequencies above the cut off frequency regardless of the intensity of photons falling on the metal surface.

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8 0
2 years ago
Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1.2 m high. Student 2 pushes an identical box up a 5 m ram
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The student who did the most work is student 2 with 2500 Joules.

<u>Given the following data:</u>

  • Force 1 = 500 Newton
  • Distance 1 = 1.2 meter
  • Force 2 = 500 Newton
  • Distance 2 = 5 meter

To determine which of the students did the most work:

Mathematically, the work done by an object is given by the formula;

Work\;done = Force \times distance

<u>For </u><u>student 1</u><u>:</u>

Work\;done = 500 \times 1.2

Work done = 600 Joules

<u>For </u><u>student 2</u><u>:</u>

Work\;done = 500 \times 5

Work done = 2500 Joules.

Therefore, the student who did the most work is student 2 with 2500 Joules.

Read more: Read more: brainly.com/question/13818347

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