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Tems11 [23]
2 years ago
13

Which is true?The photoelectric effect occurs only for frequencies below the cutoff frequency, regardless of the intensity.The p

hotoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.The photoelectric effect occurs only for frequencies below the cutoff frequency and only for intensities above a cutoff intensity.The photoelectric effect occurs only for frequencies above the cutoff frequency and only for intensities above a cutoff intensity.
Physics
2 answers:
Crank2 years ago
7 0

Answer:

The photoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.

Explanation:

The photoelectric effect occurs when light is shined on metals such as zinc beyond a certain frequency (the threshold frequency), which causes electrons to escape from the zinc. The electrons which are fleeing are called photo electrons.

Therefore photo electric effect is

The photoelectric effect occurs only for frequencies above the cutoff frequency, regardless of the intensity.

SIZIF [17.4K]2 years ago
6 0

Answer:

Explanation:

When a photon of suitable frequency falls on the metal surface, the electrons are ejected from the surface. This minimum frequency required to jest eject the electrons from the metal surface is called cut off frequency.

So, the photoelectric effect occurs only for the frequencies above the cut off frequency regardless of the intensity of photons falling on the metal surface.

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Explanation:

K E = 1/2 m v 2

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Answer:

Part A

The distance travel by the rock is approximately 132.496 m

Part B

The speed when the rock hits the ground is approximately 50.96 m/s

Explanation:

Part A

The question is focused on the kinetics equation of a free falling object

The given parameter is the time it takes the rock to hit the ground, t = 5.2 s

For an object in free fall, we have;

h = 1/2·g·t²

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The distance travel by the rock, h ≈ 132.496 m

Part B

The speed, 'v', when the rock hits the ground, is given by the following kinematic equation,

v = g·t

∴ v = 9.8 m/s² × 5.2 s = 50.96 m/s

The speed when the rock hits the ground, v ≈ 50.96 m/s.

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