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STatiana [176]
3 years ago
5

Using the equation for the final velocity in terms of masses and initial velocity of the gliders for a perfectly inelastic colli

sion, work out the final kinetic energy, assuming one of the glider is at rest initially. Compare this to the initial kinetic energy and show that kinetic energy is not conserved in the collision. Do this only with variables; none of your data should be included
Physics
1 answer:
tatuchka [14]3 years ago
4 0

Answer:

Comparison has been made.

Explanation:

Consider perfectly inelastic collision.Two masses of m1 and m2 with initial velocities u1 and u2 before colliding, stick together after collision and move with common speed v. then according to the rule of momentum preservation

m1u1+m2u2=  (m1+m2)v

v= \frac{m1u1+m2u2}{m1+m2}

If u1 and u2 are known the final common velocity can be determined

Initial kinetic energy is

\frac{1}{2}m1u1^{2}+\frac{1}{2}m2u2^{2}

The collion here is perfectly inelastic this means kinectic energy is not conserved. Therefore, initial kinectic energy is not equal to final kinectic.  

\frac{1}{2}m1v^{2}+\frac{1}{2}m2v^{2}

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Answer:

1. energy lost in the lever due to friction

3. visual estimation of height of the beanbag

5. position of the fulcrum for the lever affecting transfer of energy

Explanation:

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3 years ago
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Many industries are powered via distant power stations. Calculate the current flowing through a 7,300m long 10. copper power lin
Oliga [24]

Answer:

Current, I = 1000 A

Explanation:

It is given that,

Length of the copper wire, l = 7300 m

Resistance of copper line, R = 10 ohms

Magnetic field, B = 0.1 T

\mu_o=4\pi \times 10^{-7}\ T-m/A

Resistivity, \rho=1.72\times 10^{-8}\ \Omega-m

We need to find the current flowing the copper wire. Firstly, we need to find the radius of he power line using physical dimensions as :

R=\rho \dfrac{l}{A}

R=\rho \dfrac{l}{\pi r^2}

r=\sqrt{\dfrac{\rho l}{R\pi}}

r=\sqrt{\dfrac{1.72\times 10^{-8}\times 7300}{10\pi}}

r = 0.00199 m

or

r=1.99\times 10^{-3}\ m=2\times 10^{-3}\ m

The magnetic field on a current carrying wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

I=\dfrac{2\pi rB}{\mu_o}

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So, the current of 1000 A is flowing through the copper wire. Hence, this is the required solution.

4 0
3 years ago
A balloon is filled to a volume of 7.00*10^2 mL at a temperature of 20.0°C. The balloon is then cooled at constant pressure to a
wolverine [178]

The final volume of the gas is 238.9 mL

Explanation:

We can solve this problem by using Charle's law, which states that for a gas kept at constant pressure, the volume of the gas (V) is proportional to its absolute temperature (T):

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Which can be also re-written as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where

V_1, V_2 are the initial and final volumes of the gas

T_1, T_2 are the initial and final temperature of the gas

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V_1 = 7.00\cdot 10^2 mL = 700 mL is the initial volume

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V_2 is the final volume

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Solving for V_2,

V_2 = \frac{V_1 T_2}{T_1}=\frac{(700)(100)}{293}=238.9 mL

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3 years ago
ASK YOUR TEACHER A baseball with a mass of 146 g is thrown horizontally with a speed of 40.6 m/s (91 mi/h) at a bat. The ball is
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Answer:

Explanation:

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