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STatiana [176]
3 years ago
5

Using the equation for the final velocity in terms of masses and initial velocity of the gliders for a perfectly inelastic colli

sion, work out the final kinetic energy, assuming one of the glider is at rest initially. Compare this to the initial kinetic energy and show that kinetic energy is not conserved in the collision. Do this only with variables; none of your data should be included
Physics
1 answer:
tatuchka [14]3 years ago
4 0

Answer:

Comparison has been made.

Explanation:

Consider perfectly inelastic collision.Two masses of m1 and m2 with initial velocities u1 and u2 before colliding, stick together after collision and move with common speed v. then according to the rule of momentum preservation

m1u1+m2u2=  (m1+m2)v

v= \frac{m1u1+m2u2}{m1+m2}

If u1 and u2 are known the final common velocity can be determined

Initial kinetic energy is

\frac{1}{2}m1u1^{2}+\frac{1}{2}m2u2^{2}

The collion here is perfectly inelastic this means kinectic energy is not conserved. Therefore, initial kinectic energy is not equal to final kinectic.  

\frac{1}{2}m1v^{2}+\frac{1}{2}m2v^{2}

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Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia
Eduardwww [97]

Answer:

From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km

So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr

So runner towards the west will be

distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8

So equating east and west time we have

x/9= (11-x)/8

8x=99-9x

17x=99

x=5.92 km

That is the distance covered by runner towards the east and he will meet the runner toward the west at

6-5.92=0.08 km west of the flagpole.

7 0
3 years ago
See your name and email address.
andriy [413]

Answer:

Alfred Wegener

Explanation: Continental drift was a theory that explained how continents shift position on Earth's surface. Set forth in 1912 by Alfred Wegener, a geophysicist and meteorologist, continental drift also explained why look-alike animal and plant fossils, and similar rock formations, are found on different continents. Though most of Wegener's observations about fossils and rocks were correct, he was outlandishly wrong on a couple of key points. For instance, Wegener thought the continents might have plowed through the ocean crust like icebreakers smashing through ice.

8 0
3 years ago
Based on your book reading, what is the difference between ecosystem serveries and natural resources? Explain your response.
chubhunter [2.5K]

Answer:

Answer:This organism may be identified by its color, the spines on its back, the antennae, and therefore the long, thin body. There are many other characteristics that might even be wont to identify this organism.

Explanation:

8 0
3 years ago
What line in the sky is created by our revolution around the Sun?
faust18 [17]

Answer:

Ecliptic

Explanation:

You asked for the term that is used to describe Earth going around the sun

The ecliptic is the path the sun, moon, and planets take across the sky as seen from Earth. It best defines the plane of the Earth's orbit around the sun. The imaginary line can best be visualized in the days just before full moon.

Hope it helped

6 0
3 years ago
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
IRISSAK [1]

To develop this problem we will apply the concepts related to the Electromagnetic Force. The magnetic force can be defined as the product between the free space constant, the current (of each cable) and the length of these, on the perimeter of the cross section, in this case circular. Mathematically it can be expressed as,

F= \frac{\mu_0}{2\pi} \frac{I^2L}{d}

Here,

\mu_0 = Permeability free space

I = Current

L = Length

d= Distance between them

Our values are,

L = 0.67m

m = 0.082kg

d = 7.4*10^{-3}m

I = \text{Current through each of the wires}

Rearranging the previous equation to find the current,

\frac{mg}{L} = 2*10^{-7} (\frac{I^2}{d})

I = \sqrt{\frac{mgd}{(2*10^{-7})L}}

I = \sqrt{\frac{(0.082)(9.8)(7.4*10^{-3})}{(2*10^{-7})(0.67)}}

I = \sqrt{44377.9}

I = 210.66A

Therefore the current in the rods is 210.6A

8 0
3 years ago
Read 2 more answers
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