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2 years ago

6

Where are you likely to find a cooling plant located in the ductwork? A. A medium-sized office B. A large factory C. A single fa

mily home D. A large apartment building

1 answer:

Rufina [12.5K]2 years ago

8 0

Answer:

i think it would be B, a large factory

Explanation:

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PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!

Leya [2.2K]

Answer:

c

Explanation:

5 0

2 years ago

A man goes 150 m due east and then 200 m due north how far is he from starting point

grin007 [14]

Answer:

250 m

Explanation:

Since North and East are 90 degrees from each other, we can treat this as a right-angled triangle, with the distance in each direction being the sides and the distance from the starting point being the hypotenuse.

Hence, sqrt(150^2+200^2) = 250 m.

Hope this helped!

7 0

2 years ago

Why potential energy become equal to kinetic energy at height

Gennadij [26K]

Answer:

because potentil energy is redy to go but its bound up

And kinetic energy is in motion

Explanation:

7 0

2 years ago

Read 2 more answers

4) A drag racer starts her car from rest and accelerates at 10.0 m/s² for a distance of 400 m (1/4 mile). (a) How long did it ta

mel-nik [20]

Answer:

A) s=1/2at^2

t=√(2s/a)=√(2x400)/10.0)=9.0s

B) v=at

v=10.0x9=90m/s

3 0

2 years ago

There is a clever kitchen gadget for drying lettuce leaves after you wash them. It consists of a cylindrical container mounted s

lukranit [14]

Answer:

Option B

$a=19 m/s^{2}$

Explanation:

Given information

Radius of container, r=12cm=12/100=0.12m

Angular velocity= 2 rev/s, converted to rad/s we multiply by 2π

Angular velocity, $\omega=2*2\pi =12.56637061$

We know that speed, $v=r\omega$

Centripetal acceleration, $a=\frac {v^{2}}{r}$ and substituting $v=r\omega$ we obtain that

$a=r\omega^{2}$

Substituting \omega for 12.56637061 and r for 0.12

$a=0.12*(12.56637061)^{2}=18.94964045 m/s^{2}$

Rounded off, $a=19 m/s^{2}$

7 0

3 years ago