What information can be determined by observing dark lines within the spectrum of a given star?

When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6

Bezzdna [24]

Answer:

Distance between the charges, r = 0.8 meters

Explanation:

Given that,

Charge 1, $q_1=+8.4\ \mu C=+8.4\times 10^{-6}\ C$

Charge 2, $q_2=+5.6\ \mu C=+5.6\times 10^{-6}\ C$

Repulsive force between charges, F = 0.66 N

Let r is the distance between charges. The formula for the electrostatic force is given by :

$F=k\dfrac{q_1q_2}{r^2}$

$r=\sqrt{\dfrac{kq_1q_2}{F}}$

$r=\sqrt{\dfrac{9\times 10^9\times 8.4\times 10^{-6}\times 5.6\times 10^{-6}}{0.66}}$

r = 0.8009 meters

or

r = 0.8 meters

So, the distance between the charges i 0.8 meters. Hence, this is the required solution.

4 0

3 years ago

What must be true of a force that causes an object to move in a circular motion?

AlladinOne [14]

Before going to answer this question, first we have to understand centripetal force.

The centripetal force is the force which is required to keep the body along its circular path.The direction of the force is along the radius and towards the centre.

$Mathematically\ centripetal\ force\ F_{c} =\frac{mv^2}{r}$

Here m is the mass of the body,v is the velocity of the body and r is the radius of the circular path.

When a body moves in a circular path,its velocity at any point is the tangent drawn at that point.

As centripetal force acts along the radius, it must be perpendicular to the velocity of the body.

Hence the correct answer to the question is- It acts perpendicular to the velocity and is directed toward the center of the circle.

7 0

3 years ago

Read 2 more answers

4.) mi/hr/s and m/s/s are units for

egoroff_w [7]

Answer:

Acceleration

Explanation:

Acceleration has units of length per time squared.

6 0

3 years ago

Meeta used an elastic tape to measure the length of her window to stitch a curtain. Do you think she will be able to stitch a cu

Yuki888 [10]

Answer:

No

Explanation:

She will not be able to measure the length of her window accurately due to instrumental error from her choice of instrument. The elastic nature of her tape would alter the measurement because it will stretch as she is taking her readings, thus reducing the true measurement of the length of her window.

To measure the length of her window, she could use an inelastic tape rule or a metre rule. These instruments would eliminate instrumental error.

3 0

3 years ago

A person holding a 15.0 kg containing one 50.0 g bullet is riding on a train that is traveling at 75.0 km/h east. If the man fir

Lana71 [14]

Answer:

The velocity of the gun relative to the ground is 19.66 m/s

Explanation:

Given data,

The mass of the gun, M = 15.0 kg

The mass of the bullet, m = 50 g

The velocity of the train, v = 75 km/h

= 20.83 m/s

The velocity of bullet relative to train, V' = 350 m/s

The velocity of bullet relative to ground, V = 350 + 20

= 370 m/s

According to the law of conservation of momentum,

Mv' + mV' = 0

$v' = -\frac{mV'}{M}$

$v' = -\frac{0.050\times 350}{15}$

= -1.17 m/s

Therefore, the velocity of the gun with,

v₀ = V + v'

= 20.83 - 1.17

= 19.66 m/s

Hence, the velocity of the gun relative to the ground is 19.66 m/s

8 0

3 years ago