Question

What is the equation of the line with a slope of (3,4) that goes through the point (4,1) in slope/intercept form?

Answer 1

Hi there! :)

Step-by-step explanation:

$slope=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}$

$\frac{1-4}{4-3}=\frac{-3}{1}=-3$

Slope is -3.

Slope-intercept form: $y=mx+b$

m: represents the slope.

b: represents the y-intercept.

$y-4=-3(x-3)$

$y-4=-3x+9$

$y=-3x+13$

Final answer is y=-3x+13

Hope this helps!

:)

:D

Have a nice day! :)

Answer 2

4-1= 3
3-4= -1     slope= -3

y-4=-3(x-3)
y-4=-3x+9
y=-3x +13