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3 years ago

Marge cuts 16 pieces of tape. each piece is 3/8 inches long. how much tape did she use

Mathematics

2 answers:

Gala2k [10]3 years ago

6 0

Marge cuts 16 pieces.

Each piece has a length of 3/8 inches

she needs to cut 16 pieces of 3/8 inches each

amount of tape needed - $\frac{16}{1}*\frac{3}{8}$

when mulitplying numbers with fractions, numerators should be multiplied by numerators and denominators by denominators

$\frac{16*3}{1*8} = \frac{48}{8} = 6$

amount of tape needed = 6 inches

PilotLPTM [1.2K]3 years ago

4 0

16 x 3/8 so 16/1 x 3/8 = 48/8. 48 divided by 8 is 6. So 6 inches.

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If f(1)=7f(1)=7 and f(n)=f(n-1)+2f(n)=f(n−1)+2 then find the value of f(4)f(4).

Lady bird [3.3K]

Answer:

Step-by-step explanation: f1 =7

f2 = 5(7) + 2 = 37

f3 = 5(37) + 2 = 27

f4 = 5(9) + 2 = 47____

5 0

3 years ago

Yo plz help asapppp!!!

zysi [14]

Answer:

Arithmetic: (4, 8, 12, 16, ...) (3, 8, 13, 18, ...)

Geometric: (2, 6, 18, 54, ...) (5, 10, 20, 40, ...)

Neither arithmetic or geometric: (5, 10, 20, 30, ...)

Step-by-step explanation:

Arithmetic sequences are sequences where all of the numbers have a common difference.

4, 8, 12, 16, ... all have a common difference of 4.

3, 8, 13, 18, ... all have a common difference of 5.

Geometric sequences are sequences where all of the numbers have a common ratio.

2, 6, 18, 54, ... all have a common ratio of 3.

5, 10, 20, 40, ... all have a common ratio of 2.

Sequences that are neither arithmetic or geometric do not have common differences or common ratios.

5, 10, 20, 30, ... does not have a common difference or a common ratio

6 0

3 years ago

Read 2 more answers

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 29 ft/s. Its height

Ilia_Sergeevich [38]

Answer:

$\overline{v}_{@\Delta t=0.01s}=-15.22ft/s, \overline{v}_{@\Delta t=0.005s}=-15.11ft/s, \overline{v}_{@\Delta t=0.002s}=-15.044ft/s, \overline{v}_{@\Delta t=0.001s}=-15.022ft/s$

Step-by-step explanation:

Now, in order to solve this problem, we need to use the average velocity formula:

$\overline{v}=\frac{y_{f}-y_{0}}{t_{f}-t_{0}}$

From this point on, you have two possibilities, either you find each individual $y_{f}, y_{0}, t_{f}, t_{0}$ and input them into the formula, or you find a formula you can use to directly input the change of times. I'll take the second approach.

We know that:

$t_{f}-t_{0}=\Delta t$

and we also know that:

$t_{f}=t_{0}+\Delta t$

in order to find the final position, we can substitute this final time into the function, so we get:

$y_{f}=29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}$

so we can rewrite our formula as:

$\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-y_{0}}{\Delta t}$

$y_{0}$ will always be the same, so we can start by calculating that, we take the provided function ans evaluate it for t=1s, so we get:

$y_{0}=29t-22t^{2}$

$y_{0}=29(1)-22(1)^{2}$

$y_{0}=7ft$

we can substitute it into our average velocity equation:

$\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-7}{\Delta t}$

and we also know that the initil time will always be 1, so we can substitute it as well.

$\overline{v}=\frac{29(1+\Delta t)-22(1+\Delta t)^{2}-7}{\Delta t}$

so we can now simplify our formula by expanding the numerator:

$\overline{v}=\frac{29+29\Delta t-22(1+2\Delta t+\Delta t^{2})-7}{\Delta t}$

$\overline{v}=\frac{29+29\Delta t-22-44\Delta t-22\Delta t^{2}-7}{\Delta t}$

we can now simplify this to:

$\overline{v}=\frac{-15\Delta t-22\Delta t^{2}}{\Delta t}$

Now we can factor Δt to get:

$\overline{v}=\frac{\Delta t(-15-22\Delta t)}{\Delta t}$

and simplify

$\overline{v}=-15-22\Delta t$

Which is the equation that will represent the average speed of the ball. So now we can substitute each period into our equation so we get:

$\overline{v}_{@\Delta t=0.01s}=-15-22(0.01)=-15.22ft/s$

$\overline{v}_{@\Delta t=0.005s}=-15-22(0.005)=-15.11ft/s$

$\overline{v}_{@\Delta t=0.002s}=-15-22(0.002)=-15.044ft/s$

$\overline{v}_{@\Delta t=0.001s}=-15-22(0.001)=-15.022ft/s$

5 0

3 years ago

If f(x) = 16x – 30 and g(x) = 14x – 6, for which value of x does (f – g)(x) = 0?

san4es73 [151]

16x – 30 - (<span>14x – 6) = 0
16x - 30 - 14x + 6 =0
2x - 24 =0
2x = 24
x = 12</span>

3 0

3 years ago

Read 2 more answers

Female III-4 is pregnant via male III-5. The owner of this breeding pair wants to know the probabilities of several possible out

faust18 [17]

Answer: the following are required for IV-3 to have condition

Explanation:

-II-4 passes an X b chromosome to III-4 (probability = 1/2).

-If III-4 has the genotype X B X b (accounted for by the above probability), then she passes an X b chromosome to IV-3 (probability = 1/2).

-III-5 passes a Y chromosome to IV-3 (probability = 1/2).

All of these requirements are needed in sequence, so you apply the product rule here, too (1/2 x 1/2 x 1/2 = 1/8).

Once the individual probabilities are known, the sum and/or product rules can be used for various combinations (both conditions, either condition, etc.).

6 0

3 years ago