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3 years ago

Marge cuts 16 pieces of tape. each piece is 3/8 inches long. how much tape did she use

Mathematics

2 answers:

Gala2k [10]3 years ago

6 0

Marge cuts 16 pieces.

Each piece has a length of 3/8 inches

she needs to cut 16 pieces of 3/8 inches each

amount of tape needed - $\frac{16}{1}*\frac{3}{8}$

when mulitplying numbers with fractions, numerators should be multiplied by numerators and denominators by denominators

$\frac{16*3}{1*8} = \frac{48}{8} = 6$

amount of tape needed = 6 inches

PilotLPTM [1.2K]3 years ago

4 0

16 x 3/8 so 16/1 x 3/8 = 48/8. 48 divided by 8 is 6. So 6 inches.

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Which is the equation of a hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0)? y squared over 40 minus x square

N76 [4]

The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is $\frac{x^2}{10} + \frac{y^2}{15} = 1$

<h3>How to determine the equation of the hyperbola?</h3>

The given parameters are:

Directrices at x = ±2
Foci at (5, 0) and (−5, 0)

The foci of a hyperbola are represented as:

Foci = (k ± c, h)

The center is:

Center = (h,k)

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Directrix, x = h ± a²/c

By comparison, we have:

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a²/c = 2

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k ± c = 0 ± 5

By comparison, we have:

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Substitute c = 5 in a² = 2c

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Next, we calculate b using:

b² = c² - a²

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The hyperbola is represented as:

$\frac{(x - k)^2}{a^2} + \frac{(y - h)^2}{b^2} = 1$

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$\frac{(x - 0)^2}{10} + \frac{(y - 0)^2}{15} = 1$

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$\frac{x^2}{10} + \frac{y^2}{15} = 1$

Hence, the equation of the hyperbola is $\frac{x^2}{10} + \frac{y^2}{15} = 1$

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3 years ago

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