All categories

4 years ago

What is the answer to this problem 3x+6(x-4)

Mathematics

2 answers:

Lubov Fominskaja [6]4 years ago

8 0

Explanation:

Distributive property: → $a(b+c)=ab+ac$

Expand equation.

$6(x-4)$

Then, multiply 6*4.

$6*4=24$

$=3x+6x-24$

Add by similar elements.

$6+3=9$

Don't forget to used variable with letter/symbol.

$\boxed{9x-24}$

Hope this helps!

Thank you!

Have a great day!

-Charlie

charle [14.2K]4 years ago

3 0

Hey there!

Answer = 9x - 24

Let's simplify step-by-step.

3x + 6(x - 4)

Distribute:

= 3x + (6)(x) + (6)(-4)

= 3x + 6x + -24

Combine Like terms:

= 3x + 6x + -24

= (3x + 6x + (-24)

= 9x + -24

= 9x - 24

So therefore, that is how you found your answer: 9x - 24

You might be interested in

The wages

mihalych1998 [28]

Answer:

£ 144

Step-by-step explanation:

the formula would be :

w = n * r

finding the wages for 20 hours at a rate of 7.20 hours can be solved like this:

w = n *r

w = 7.20 * 20

<u>w =£ 144</u>

<u />

8 0

3 years ago

find an equation of the tangent plane to the given parametric surface at the specified point. x = u v, y = 2u2, z = u − v; (2, 2

Alexxandr [17]

The surface is parameterized by

$\vec s(u,v) = x(u, v) \, \vec\imath + y(u, v) \, \vec\jmath + z(u, v)) \, \vec k$

and the normal to the surface is given by the cross product of the partial derivatives of $\vec s$ :

$\vec n = \dfrac{\partial \vec s}{\partial u} \times \dfrac{\partial \vec s}{\partial v}$

It looks like you're given

$\begin{cases}x(u, v) = u + v\\y(u, v) = 2u^2\\z(u, v) = u - v\end{cases}$

Then the normal vector is

$\vec n = \left(\vec\imath + 4u \, \vec\jmath + \vec k\right) \times \left(\vec \imath - \vec k\right) = -4u\,\vec\imath + 2 \,\vec\jmath - 4u\,\vec k$

Now, the point (2, 2, 0) corresponds to u and v such that

$\begin{cases}u + v = 2\\2u^2 = 2\\u - v = 0\end{cases}$

and solving gives $u = v = 1$ , so the normal vector at the point we care about is

$\vec n = -4\,\vec\imath+2\,\vec\jmath-4\,\vec k$

Then the equation of the tangent plane is

$\left(-4\,\vec\imath + 2\,\vec\jmath - 4\,\vec k\right) \cdot \left((x-2)\,\vec\imath + (y-2)\,\vec\jmath + (z-0)\,\vec k\right) = 0$

$-4(x-2) + 2(y-2) - 4z = 0$

$\boxed{2x - y + 2z = 2}$

6 0

2 years ago

A company employs 400 salespeople. Of these, 83 received a bonus last year, 100 attended a special sales training program at the

andrey2020 [161]

Answer:

21/50

Step-by-step explanation:

Total Number of salespeople in company = 400

Of these salespeople, number of people recieved bonus last year = 83

Number of salesperson attended special sales training = 100

And, Number of salesperson attended both special sales training and received a bonus = 42

Then proportion of salesperson who attended special sales training program and received bonus = Number of salesperson attended both special sales program and received a bonus / total number of salesperson attended special sales training

= 42/100

= 21/50

8 0

3 years ago

Read 2 more answers

Suppose that we roll a fair die until a 6 comes up.

shtirl [24]

The probability is 1/36
36

8 0

4 years ago

Prove that T is one to one if and only if T carries linearly independent subsets of V onto linearly independent subsets of W.

balu736 [363]