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Nastasia [14]
3 years ago
13

An experienced pool player can control the placement of a ball after it hits an edge bumper by putting spin, or "English," on th

e ball. This is accomplished by aiming the cue stick so that it hits the ball either left or right of the ball's center. Suppose a player gives a ball English by hitting it to the left of center (left from his perspective).Which path in does the ball take after it collides with the bumper?Account for this behavior.
Physics
1 answer:
IgorLugansk [536]3 years ago
4 0

Answer:

The ball will take path 'c' after colliding with the bumper.

Explanation:

If the ball is made not to spin, then it will deflect along path b

From above, If the ball spin clockwise and the point of the ball is in contact with the edge of the table stops for a moment during the collision.

Due to the angular momentum of the ball, the ball would be forced to move towards the left. The rotational velocity will be initially downward because cue  made the ball to rotate in the clockwise direction. For the ball to spin less there will be some torque acting on the ball which will cause acceleration in the counterclockwise direction.

The edge of the table produce the required acceleration.  i.e a force have to be exerted by the edge of the table on the ball with a component to the left as viewed from the player's perspective.

Therefore, the ball will take path'c' after colliding with the bumper.

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In Trial III, a different, looser, spring is used; its force constant is 23.1 N/m. The suspended mass is the same as the one in
cricket20 [7]

Answer:

T=0.827s

Explanation:

The period of a spring can be calculated with the equation

T=2\pi w

But we know as well that w is given by,

w=\sqrt{\frac{k}{m}}

Replacing,

w=\frac{2\pi}{T}= \sqrt{\frac{k}{m}}\\T=2\pi\sqrt{\frac{k}{m}}\\T=2\pi\sqrt{\frac{0.4}{23.1}}

So we have that

T=0.827s

7 0
3 years ago
Find the radius RRigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×
Lera25 [3.4K]

Answer:

r=5.1\times10^{10}m

Explanation:

The Stefan–Boltzmann law for a black body (as stars are treated) can be written as j^*=\sigma T^4, where j^* is the total energy radiated per unit surface area across all wavelengths per unit time, T the absolute temperature and \sigma=5.67\times10^{-8} Wm^{-2}K^{-4} is the Stefan–Boltzmann constant.

If we multiply j* by the surface area A of the star we get the total energy radiated across all wavelengths per unit time, which is the total power radiated, so we can write:

P=Aj^*=A\sigma T^4=4\pi r^2\sigma T^4

where we have used the formula for the surface area of a sphere A=4\pi r^2

Solving for r we have:

r=\sqrt{\frac{P}{4\pi \sigma T^4}}=\sqrt{\frac{2.7\times10^{31}W}{4\pi (5.67\times^{-8}Wm^{-2}K^{-4})(11000K)^4}}=5.1\times10^{10}m

7 0
4 years ago
What kind of energy involves the flow of positive charges?
Neporo4naja [7]
Electrical would be the energy that involves the flow of positive charges.
8 0
3 years ago
Read 2 more answers
A boat moves through the water with two forces acting on it. One is a 2.96×10^3 N forward push by the motor, and the other is a
notka56 [123]

Answer:

(a) 0.984781 m/s^{2}

(b) 157.76679 m

(c) 17.62757 m/s

Explanation:

Net force acting, F_{net}=2.96*10^{3}-1.86*10^{3}=1.1*10^{3}N

Acceleration, a=\frac {F_{net}}{m} where m is the mass

a=\frac {1.1*10^{3}}{1117}= 0.984781 m/s^{2}

(b)

From kinematic equation

s=ut+0.5at^{2} where s is displacement, u is initial velocity, t is time taken and a is acceleration.

Considering that u=0 since it starts at rest

s=0.5at^{2} and substituting the value of a as calculated in part a, t is 17.9 s hence

s=0.5*0.984781*17.9^{2}=157.76679 m

(c )

From kinematic equation

v=u+at where u and v are initial and final velocities respectively, a is acceleration and t is duration in seconds. Since it starts from rest, u=0 and substituting the value of a as found in part a, t given as 17.9 s we get

V=0+0.984781*17.9=17.62757 m/s

8 0
3 years ago
What is the momentum of a 1.5 × 103 kilogram van that is moving at a velocity of 32 meters/second?
uysha [10]

Answer:

The answer is

<h2>4.8 × 10⁴ kg. m/s</h2>

Explanation:

Momentum of a body is given by

p = m× v

where m is the mass of the body

v is the velocity

p is the momentum

From the question

m = 1.5 × 10³kg

v = 32m / s

So the momentum is

p = 1.5 × 10³kg × 32m/s

p = 48 000 kg. m/s

<h3>p = 4.8 × 10⁴ kg. m/s</h3>

Hope this helps you

6 0
3 years ago
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