Question

One strategy in a snowball fight is to throw

Answer 1

second question: How many seconds after the first snowball

should you throw the second so that they

arrive on target at the same time?

Answer in units of s.

Answer:

Part 1: 28°

Part 2: 1.367

Explanation:

Part 1:

Given: 62°  

Simple

θ = 90°- 62°

θ = 28°

Part 2:

Y-direction

Δy$=v_{yo} t+\frac{1}{2} a_{y} t^{2}$

$0=[16.2sin(62)]t_{1}+1/2(-9.8)t_{1}^{2}$

$t_{1} =\frac{2[16.2sin(62)]}{9.8}$

$t_{1}=2.91913s$

$0=[16.2sin(28)]t_{2}+1/2(-9.8)t_{2}^{2}$

$t_{2} =\frac{2[16.2sin(28)]}{9.8}$

$t_{2}=1.55213s$

Δt$=t_{1}-t_{2}$

Δt$=2.91913-1.55213$

Δt= 1.367s

Hope it helps :)