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Arlecino [84]
2 years ago
14

Which of the following choices is not an example of climate?

Physics
1 answer:
Sedbober [7]2 years ago
5 0

Answer:

Florida is tropical, with a significant rainy seson

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Marc attaches a falling 500-kg object with a rope through a pulley to a paddle wheel shaft. He places the system in a well-insul
Klio2033 [76]

Answer:

4.68227 °C

Explanation:

m_o = Mass of object = 500 kg

m_w = Mass of water = 25 kg

c = Specific heat of water at 20°C = 4186 J/kg°C

h = Height from which the object falls = 100 m

g = Acceleration due to gravity = 9.8 m/s²

The potential energy and heat will balance each other

PE=Q\\\Rightarrowmc m_ogh=m_oc\Delta T\\\Rightarrow \Delta T=\frac{m_ogh}{m_oc}\\\Rightarrow \Delta T=\frac{500\times 9.8\times 100}{25\times 4186}\\\Rightarrow \Delta=4.68227\ ^{\circ}C

The temperature change in the water is 4.68227 °C

5 0
3 years ago
Jill is pushing a box across the floor. Which represents the upward force perpendicular to the floor?
Georgia [21]

Answer:

When Jill is pushing a box across a floor, it represents the upward motion and it is natural force is applied.

So it is represented as FN and normal force takes place in considering the force perpendicular to the floor.

It seems to support that forced applied on an object when the object is in contact with other.

Explanation:

5 0
2 years ago
Two particles, each of mass 7.0 kg, are a distance 3.0 m apart. To bring a third particle, with mass 21 kg, from far away to a r
garri49 [273]

Answer: the external agent must do work equal to -1.3 × 10⁻⁸ J

Explanation:

Given that;

Mass M1 = 7.0 kg

r = 3.0/2 m = 1.5 m

Mass M2 = 21 kg

we know that G = 6.67 × 10⁻¹¹ N.m²/kg²

work done by an external agent W = -2GM2M1 / r

so we substitute

W = (-2 × 6.67 × 10⁻¹¹ × 21 × 7) / 1.5

W = -1.96098 × 10⁻⁸ / 1.5

W = -1.3 × 10⁻⁸ J

Therefore the external agent must do work equal to -1.3 × 10⁻⁸ J

8 0
3 years ago
The density of gold is 19.3 g cm³. What is the mass of a bar of gold in Kg that measures 6 cm x 4 cmx to 2 cm ?
klemol [59]

Answer: 0.9264 kg

Explanation: [I'll use "cc" for cubic centimeter, instead of cm^3.

The volume is 6cm*4cm*2cm = 48 cm^3 (cc).

Density of Au is 19.3 g/cc

Mass of gold = (48 cc)*(9.3 g/cc) = 926.4 grams Au

1 kg = 1,000 g

(926.4 grams Au)*(1 kg/1,000 g) = 0.9264 kg, 0.93 kg to 2 sig figs

At gold's current price of $57,500/kg, this bar is worth $53,268. Keep it hidden from your lab partner (and instructor).

3 0
2 years ago
How long does it take for a Ford Econoline van moving at 39.5 m/s to travel 600 m?
Andrej [43]

Answer: B. 15.2s

Explanation: 600/39.5 = about 15.2

6 0
3 years ago
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