Which of the following choices is not an example of climate?

Q/C An undersea earthquake or a landslide can produce an ocean wave of short duration carrying great energy, called a tsunami. W

iragen [17]

The amplitude $A_{2}$ is 8.307 m

When describing the peak value of a quantity, such as the level of sound waves or the power and voltage in electrical and electronic systems, the term amplitude is employed. A louder sound has a bigger amplitude, and a softer sound has a smaller amplitude.

As we previously discussed in the concept session, the square root of the water's speed is inversely related to the amplitude of its waves.

$A\alpha\frac{1}{\sqrt{v} }$

Solve for first case:

$A_{1}=\frac{1}{\sqrt{v_{1} } }$

Solve for second case:

$A_{2}=\frac{1}{\sqrt{v_{2} } }$

So, the two equations is equal

$A^{2} _{1} v_{1} = A^{2} _{2} v_{2}$

$=A^{2} _{2} \sqrt{g d_{2} }$

Rearrange and solve for the amplitude $A_{2}$ :

$A_{2} =\sqrt{\frac{A^{2}_{1} v_{1} }{v_{2} } }$

$=\sqrt{\frac{A^{2}_{1} v_{1} }{\sqrt{g d_{2} } } }$

$=\sqrt{\frac{(1.8m)^{2} X200 m/s }{\sqrt{9.8m/s^{2}X9 m } } }$

= 8.307 m

So, The amplitude $A_{2}$ is 8.307 m.

Learn more about amplitude here:

brainly.com/question/3613222

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7 0

1 year ago

State ohms law and explain the terms associated with it

stich3 [128]

Explanation:

Ohm's Law is a formula used to calculate the relationship between voltage, current and resistance in an electrical circuit. To students of electronics, Ohm's Law (E = IR)

3 0

3 years ago

Read 2 more answers

What are 3 pros and cons of nuclear transmutation?

Tanya [424]

Pros -

It doesn't cost much
Power stations are very compact
Transportation of the material is easy

Cons-

It's not safe
Nuclear waste take 200 years to degrade
Greater risk of explosion

-IF THIS HELPED WHICH I HOPE COMMENT BELOWw ↓PLEASEX . THANKs!

6 0

3 years ago

Read 2 more answers

A rock band playing an outdoor concert produces sound at 120 dB 5.0 m away from their single working loudspeaker. What is the so

joja [24]

ANSWER:100dB

from the sound intensity level,the sound intensity is calculated as:

$\beta$ ₁= $\beta$ =(10dB)㏒₁₀(l₁/l₀)

inserting numbers:

120dB=(10dB)㏒₁₀[l₁/10⁻¹²W/m⁸] or 12=㏒₁₀[l₁/(10⁻¹²)W/m²

Getting the antilog of both sides and obtain 10¹²=l₁(10⁻¹²W/m²)which

can be used to solve for l₁ and get

l₁=(10⁻¹²W/m²)(10¹²)=1 W/m²

since the sound intensity is related to the power and that the power does not change,the sound intensity at any other point can be solved.Plugging-in

ᵃ = 4πr²,into P=l₁ₐ₁=l₂ₐ₂ and get:

l₂=l₁(r₁/r₂)² =(1W/m²)(5/35) =2.04×10⁻²W/m²

since we know the sound intensity at the sound point 2r,the sound intensity level at the point can be solved.We have:

$\beta$ ₂= $\beta$ =(10dB)㏒₁₀(l₂/l₀)=(10dB)㏒₁₀(2.04×10⁻²/1×10⁻²)

$\beta$ ₂=(10dB)㏒₁₀(2.04×10¹⁰)

$\beta$ =(10dB)[㏒₁₀(2.04)+㏒₁₀(10¹⁰)]=10dB[0.32+10]=103dB=100dB

3 0

3 years ago

Sabiendo que el indice de refracción dela gua es 1,33 calcula el ángulo de refracción resultante para un rayo de luz que incide

Kaylis [27]

Answer:

35.16 degrees

Explanation:

Knowing that the index of refraction of the guide is 1.33, calculate the resulting angle of refraction for a ray of light that falls on a pool with an angle of incidence of 50º

Refractive index, n = 1.33

The angle of incidence, i = 50°

We need to find the angle of refraction. let it is r. It can be calculated using Snells law as follows:

$n=\dfrac{\sin i}{\sin r}\\\\\sin r=\dfrac{\sin i}{n}\\\\r=\sin^{-1}(\dfrac{\sin i}{n})\\\\r=\sin^{-1}(\dfrac{\sin 50}{1.33})\\\\r=35.16^{\circ}$

So, the angle of refraction is 35.16 degrees.

3 0

2 years ago