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jenyasd209 [6]
3 years ago
10

The combustion of ethanol ( C 2 H 6 O) produces

Chemistry
2 answers:
lana [24]3 years ago
8 0

Answer: C2H6O + 3O2 > 2CO2 + 3H2O

Explanation: in a combustion reaction hydrocarbons reacts with oxygen gas to produce carbon dioxide and water. After predicting the products balance the chemical equation.

nika2105 [10]3 years ago
7 0

Answer:

C2H6O + 3O2 —> 2CO2 + 3H2O

Explanation:

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A sample of gas initially has a volume of 2.25 L at 350 K and a pressure of 1.75 atm. What will be sample pressure if the volume
IRINA_888 [86]

Answer:

8.44 atm

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 2.25 L

Initial temperature (T₁) = 350 K

Initial pressure (P₁) = 1.75 atm

Final volume (V₂) = 1 L

Final temperature (T₂) = 750 K

Final pressure (P₂) =?

The final pressure of the gas can be obtained as illustrated below:

P₁V₁/T₁ = P₂V₂/T₂

1.75 × 2.25 / 350 = P₂ × 1 / 750

3.9375 / 350 = P₂ / 750

Cross multiply

350 × P₂ = 3.9375 × 750

350 × P₂ = 2953.125

Divide both side by 350

P₂ = 2953.125 / 350

P₂ = 8.44 atm

Thus, the final pressure of the gas is 8.44 atm.

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3 years ago
An organic compound containing C,H and O only. Has 29.6% O by mass. Its relative .olecular mass is 270. How many Oxygen atoms ar
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12.1% C, 16.1% O, 71.8% Cl

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3 years ago
Calculate the work (kJ) done during a reaction in which the internal volume expands from 20 L to 43 L against an outside pressur
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\large \boxed{\text{-10.0 kJ}}

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1. Calculate the work

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2. Convert litre-atmospheres to joules

w = \text{-98.9 L\cdot$atm } \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm }} = \text{-10000 J} = \textbf{-10.0 kJ}\\\\\text{The work done is $\large \boxed{\textbf{-10.0 kJ}}$}

The negative sign indicates that the work was done against the surroundings.

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Explanation:

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2. What will you change (the independent variable) in each test?
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