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Marizza181 [45]
2 years ago
12

what is the effect of using higher concentration of sodium hydrogen carbonate on the rate of reaction?

Chemistry
1 answer:
Alex2 years ago
7 0
Increasing the concentration of one or more reactants will often increase the rate of reaction. This occurs because a higher concentration of a reactant will lead to more collisions of that reactant in a specific time period.

Reaction rate increases with concentration, as described by the rate law and explained by collision theory. As reactant concentration increases, the frequency of collision increases. The rate of gaseous reactions increases with pressure, which is, in fact, equivalent to an increase in concentration of the gas.
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How many oxygen molecules are needed to make 10 carbon dioxide molecules according to the following balanced chemical equation?
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<h2 /><h2 /><h2>answer.</h2>

five oxygen molecules

step by step explanation.

according to the equation,one molecule of oxygen is enough to react with two carbon molecules thus 10 carbon molecules need 5oxygen molecules

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2 years ago
What kind of chemical bond holds each oxygen atom to the phosphorus atom
MAXImum [283]
This I believe would be double covalent bonds
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What are the products produced when an acid and base react together
SashulF [63]
Both products will start to cancel the acidity and how strong the base is if they are mixed. If the acid is stronger than the base then it will be an acidic product and visa versa if the base is stronger than the acid.
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Read 2 more answers
Researchers can use solvents to extract, or break apart, components of a cell or tissue to separate and/or isolate components. I
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The cell membrane which is more fat permeable will be present at the end of the process.

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Learn more:brainly.com/question/14396802

6 0
2 years ago
A volume of 90.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2
Alja [10]

Answer:

0.823 M was the molarity of the KOH solution.

Explanation:

H_2SO_4+KOH\rightarrow K_2SO_4+2H_2O (Neutralization reaction)

To calculate the concentration of base , we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=2\\M_1=1.50 M\\V_1=24.7 mL\\n_2=1\\M_2=?\\V_2=90.0 mL

Putting values in above equation, we get:

2\times \1.50 M\times 24.7 mL=1\times M_2\times 90.0 mL

M_2=\frac{2\times 1.50M\times 24.7 mL}{1\times 90.0 mL}=0.823 M

0.823 M was the molarity of the KOH solution.

7 0
2 years ago
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