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Stolb23 [73]
3 years ago
5

A sample of krypton gas in a container of volume 1.90 L exerts a pressure of 0.553 atm at 21 Celsius. How many moles of gas are

present?
Chemistry
2 answers:
Scilla [17]3 years ago
6 0

Answer:

0.044 mole

Explanation:

Data obtained from the question include:

V (volume) = 1.90 L

P (pressure) = 0.553 atm

T (temperature) = 21°C = 21 + 273 = 294K

R (gas constant) = 0.082atm.L/Kmol

n (number of mole of krypton) =?

Using the ideal gas equation PV = nRT, the number of mole of krypton can obtained as illustrated below:

PV = nRT

n = PV /RT

n = (0.553 x 1.9)/(0.082x294)

n = 0.044 mole

Therefore, 0.044 mole of krypton is present in the container.

NeTakaya3 years ago
3 0

Explanation:

pv = nRT

n= PV/RT

n =0.553×1.90/0.0821×294

n=1.0507/24.1374

n=0.0435mol

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4 0
2 years ago
How many moles are in 1.505x10^24 molecules of surcrose
algol [13]

Answer:

2.499 moles of sucrose

Explanation:

Divide by Avogadro's number

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3 years ago
Which of the following elements has six valence electrons?<br> Be<br> B<br> C<br> N<br> O
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Oxygen (O) ,Neon (Ne),Argon (Ar)
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3 years ago
Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.2
Rina8888 [55]

Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

Answer 1) σ Bond a : C has SP^{2}  O has SP^{2} .

Explanation : The orbitals of oxygen and carbon which are involved in SP^{2} hybridization to form sigma bonds. This is observed at 'a' position in the citric acid molecule.

Answer 2) π Bond a: C has π orbitals and  O also has π  orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b:  O SP^{3}  H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen SP^{3} hydrogen atoms in it. It has SP^{3} hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c:   C is SP^{3}  O is also SP^{3}

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of SP^{3} hybridized bonds.

Answer 5) Bond d:   C atom has SP^{3}  C atom has SP^{3}

Explanation : At the position of 'd' the bonding between two carbon atoms is found to be SP^{3}. Therefore, the orbitals that undergo SP^{3} hybridization are SP^{3}.

Answer 6) Bond e : C1 containing O SP^{2}    

C2 is SP^{3}

Explanation : The carbon atom which contains oxygen along with a double bond has SP^{2} hybridized orbitals involved in the bonding process; whereas the carbon at C2 has SP^{3} hybridized orbitals involved during the bonding. This is for the 'e' position.

7 0
3 years ago
2. What's the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity of 10 m/s?
Dennis_Churaev [7]
<h2>Let us solve for it </h2>

Explanation:

Energy

It is ability to do work .

There are so many forms of energy .

out of which mechanical energy is also one of the form .

Mechanical energy

It is the energy possessed by the body by virtue of its motion and state .

It is of two types :

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Kinetic energy

It is the energy possessed by the body by virtue of its motion .

Its expression is :

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K.E will be = 1/2 x 2 x 10 x 10

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8 0
3 years ago
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