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Stolb23 [73]
3 years ago
5

A sample of krypton gas in a container of volume 1.90 L exerts a pressure of 0.553 atm at 21 Celsius. How many moles of gas are

present?
Chemistry
2 answers:
Scilla [17]3 years ago
6 0

Answer:

0.044 mole

Explanation:

Data obtained from the question include:

V (volume) = 1.90 L

P (pressure) = 0.553 atm

T (temperature) = 21°C = 21 + 273 = 294K

R (gas constant) = 0.082atm.L/Kmol

n (number of mole of krypton) =?

Using the ideal gas equation PV = nRT, the number of mole of krypton can obtained as illustrated below:

PV = nRT

n = PV /RT

n = (0.553 x 1.9)/(0.082x294)

n = 0.044 mole

Therefore, 0.044 mole of krypton is present in the container.

NeTakaya3 years ago
3 0

Explanation:

pv = nRT

n= PV/RT

n =0.553×1.90/0.0821×294

n=1.0507/24.1374

n=0.0435mol

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