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ki77a [65]
3 years ago
9

The basic behind equal driving is to

Engineering
1 answer:
vlabodo [156]3 years ago
4 0

Follow traffic signs , Keep distance between cars , Be patient in traffic.

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Troy must keep track of the amount of refrigerant he uses from a 50-pound cylinder to ensure that accurate
IgorLugansk [536]

Answer:

Amount of gas still in cylinder = 28 pound

Explanation:

Given:

Amount of gas in cylinder = 50 pound

Amount of gas used in Ms. Jones system = 13 pound

Amount of gas used in client system = 9 pound

Find:

Amount of gas still in cylinder

Computation:

Amount of gas still in cylinder = Amount of gas in cylinder - Amount of gas used in Ms. Jones system - Amount of gas used in client system

Amount of gas still in cylinder = 50 - 13 - 9

Amount of gas still in cylinder = 28 pound

7 0
3 years ago
Just like this for 772+e
MrMuchimi

Answer:

ok, thx dude ^.^

Explanation:

6 0
3 years ago
where σ(t) and σ(0) represents the time-dependent and initial (i.e., time =0) stresses, respectively, and t and τ denote elapsed
artcher [175]

Answer:

MUDA MUDA A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.

Explanation:

4 0
4 years ago
A local zoo wants to keep track of how many pounds of food each of its three monkeys eats each day during a typical week. Write
Kryger [21]

Answer:

#include<iostream>

using namespace std;

int main()

{

  double data[3][5],avg,least,most,total;

  int leastNum,mostNum;

  for(int i=0;i<3;i++)

  {

      cout<<"Enter quantity of food for monkey "<<i+1<<":\n";

      for(int j=0;j<5;j++)

      {

          cout<<"Day "<<j+1<<": ";

          cin>>data[i][j];

      }

  }

  least = data[0][0];

  most = data[0][0];

  for(int i = 0;i<3;i++)

  {

      for(int j = 0;j<5;j++)

      {

          total+=data[i][j];

          if(data[i][j]>most)

          {

              most=data[i][j];

              mostNum=i+1;    

          }

          if(data[i][j]<least)

          {

              least=data[i][j];

              leastNum=i+1;

             

          }

      }

  }

  avg=total/5.0;

  cout<<"Average food eaten in a day by all the 3 monkeys: "<<avg<<endl;

  cout<<"Most amount of food eaten in a day: "<<most<<" by monkey: "<<mostNum<<endl;

  cout<<"Least amount of food eaten in a day: "<<least<<" by monkey: "<<leastNum<<endl;

  return 0;

}

6 0
4 years ago
Dial CALIPER ZOOM INNNN
taurus [48]

Answer:

1.142 and 5.621

.

Explanation:

........

8 0
3 years ago
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