Answer:
total weight of aggregate = 5627528 lbs = 2814 tons
Explanation:
given data
dry density = 119.7 lb/cu ft
area = 2000 ft × 48 ft × 6 in
aggregate = 3.1%
required compaction = 95%
solution
we get here volume of space to be filled with aggregate that is
volume = 2000 × 48 × 0.5 = 48000 ft³
when here space fill with aggregate of density is
density = 0.95 × 119.7 = 113.72 lb/ft³
and
dry weight of this aggregate will be is
dry weight = 48000 × 113.72 = 5458320 lbs
and
we consider take percent moisture by weigh so that there weight of moisture in aggregate is express as
weight of moisture = 0.031 × 5458320 = 169208 lbs
and
total weight of aggregate will be
total weight of aggregate = 5458320 + 169208
total weight of aggregate = 5627528 lbs = 2814 tons
