Determine the average power, complex power and power factor (including whether it is leading or lagging) for a load circuit whos
e voltage and current at its input terminals are given by: v(t) = 100cos(377t-30)v, i(t) = 2.5cos(377t-60)A
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Answer:
Head loss is 1.64
Explanation:
Given data:
Length (L) = 200 m
Discharge (Q) = 0.16 m3/s
According to table of nominal pipe size , for schedule 80 , NPS 14, pipe has diameter (D)= 12.5 in or 31.8 cm 0.318 m
We know,
where, f = Darcy friction factor
V = flow velocity
g = acceleration due to gravity
We know, flow rate Q = A x V
solving for V
obtained Darcy friction factor
calculate Reynold number (Re) ,
where, = density of water
= Dynamic viscosity of water at 15 degree C = 0.001 Ns/m2
so reynold number is
= 6.4 x 10^5
For Schedule 80 PVC pipes , roughness (e) is 0.0015 mm
Relative roughness (e/D) = 0.0015 / 318 = 0.00005
from Moody diagram, for Re = 640000 and e/D = 0.00005 , Darcy friction factor , f = 0.0126
Therefore head loss is
HL = 1.64 m
#include
int main () {
printf("Program to calculate the square footage of the house.\n");
int total_rooms;
double length, width;
double total_square_footage = 0.0;
printf("Enter total number of rooms in the house:");
scanf("%d", &total_rooms);
for (int i = 0; i
printf("Enter the lenght and width of room %d: ", i+1);
scanf("%if %if", &lenght, &width);
total_square_footage += lenght*width;
}
printf("Total square footage of the house: %if\n", total_square_footage);
return 0;
}
Please mark it as brainliest answer:).
int main () {
printf("Program to calculate the square footage of the house.\n");
int total_rooms;
double length, width;
double total_square_footage = 0.0;
printf("Enter total number of rooms in the house:");
scanf("%d", &total_rooms);
for (int i = 0; i
printf("Enter the lenght and width of room %d: ", i+1);
scanf("%if %if", &lenght, &width);
total_square_footage += lenght*width;
}
printf("Total square footage of the house: %if\n", total_square_footage);
return 0;
}
Please mark it as brainliest answer:).