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BabaBlast [244]
3 years ago
9

Determine the average power, complex power and power factor (including whether it is leading or lagging) for a load circuit whos

e voltage and current at its input terminals are given by: v(t) = 100cos(377t-30)v, i(t) = 2.5cos(377t-60)A

Engineering
2 answers:
Charra [1.4K]3 years ago
6 0

Answer:

Average power: 108.25 W

Complex power: 125 VA

Power factor: 0.866

Refer below for the explanation.

Explanation:

Refer to the picture for brief explanation.

Paul [167]3 years ago
4 0

Answer:

Average power = 108.25W

Complex power = 125W

PF = 0.866

Explanation:

Check attachment for step by step instructions.

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Answer:

<h2>The purposes of public participation are to promote transparency, encourage openness in government, and build ownership of development decisions as well as programmes and projects. Public participation encourages citizens to be more engaged in the decision-making processes that have an impact on their local community.</h2>

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3 years ago
The pressure distribution over a section of a two-dimensional wing at 4 degrees of incidence may be approximated as follows: Upp
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Answer:

The lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

Explanation:

The Upper Surface Cp is given as

Cp_u=-0.8 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.8*0.6+0.4*0.1

The Lower Surface Cp is given as

Cp_l=-0.4 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.4*0.6+0.4*0.1

The difference of the Cp over the airfoil is given as

\Delta Cp=Cp_l-Cp_u\\\Delta Cp=-0.4*0.6+0.4*0.1-(-0.8*0.6-0.4*0.1)\\\Delta Cp=-0.4*0.6+0.4*0.1+0.8*0.6+0.4*0.1\\\Delta Cp=0.4*0.6+0.4*0.2\\\Delta Cp=0.32

Now the Lift Coefficient is given as

C_L=\Delta C_p cos(\alpha_i)\\C_L=0.32\times cos(4*\frac{\pi}{180})\\C_L=0.3192

Now the coefficient of moment about the leading edge is given as

C_M=-0.3*0.4*0.6-(0.6+\dfrac{0.4}{3})*0.2*0.4\\C_M=-0.1306

So the lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

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3 years ago
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Air is to be compressed so that its volume is reduced to half of its original volume if the initial pressure is 200 kPa and the
Alex_Xolod [135]

Answer:

P_{2} = 527.803\,kPa

Explanation:

The politropic relationship for a isentropic process is:

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Where \gamma is the ratio of specific heats

The final pressure is:

P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}}\right)^{\gamma}

P_{2} = (200\,kPa)\cdot (2)^{1.4}

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