PLEASE HELP........Compare and contrast microwaves with visible light using wavelength frequency and energy.
2 answers:
Microwaves heat up food. Ha just kidding!
Microwaves are lower on the spectrum. They emit less energy and have longer wavelengths. Light Waves emit more energy and have shorter wavelengths than Microwaves. Light Waves can be seen by the naked eye. Both of these waves are harmless and emit low energy, compared to waves higher in the spectrum that have smaller wavelengths, therefore more energy. Some examples are Gamma rays and X-rays, emitting high levels of energy and even radiation.
Hope that makes sense! :V
Microwaves are lower on the spectrum. They emit less energy and have longer wavelengths. Light Waves emit more energy and have shorter wavelengths than Microwaves. Light Waves can be seen by the naked eye. Both of these waves are harmless and emit low energy, compared to waves higher in the spectrum that have smaller wavelengths, therefore more energy. Some examples are Gamma rays and X-rays, emitting high levels of energy and even radiation.
Hope that makes sense! :V
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Answer:
2.86 m
Explanation:
Given:
M₁ = 10 kg
M₂ = 5 kg
= 0.5
height, h = 5 m
distance traveled, s = 2 m
spring constant, k = 250 N/m
now,
the initial velocity of the first block as it approaches the second block
u₁ = √(2 × g × h)
or
u₁ = √(2 × 9.8 × 5)
or
u₁ = 9.89 m/s
let the velocity of second ball be v₂
now from the conservation of momentum, we have
M₁ × u₁ = M₂ × v₂
on substituting the values, we get
10 × 9.89 = 5 × v₂
or
v₂ = 19.79 m/s
now,
let the velocity of mass 2 when it reaches the spring be v₃
from the work energy theorem, we have
Work done by the friction force = change in kinetic energy of the mass 2
or
or
v₃ = 20.27 m/s
now, let the spring is compressed by the distance 'x'
therefore, from the conservation of energy
we have
Energy of the spring = Kinetic energy of the mass 2
or
on substituting the values, we get
or
x = 2.86 m
Answer:
h = 2.64 meters
Explanation:
It is given that,
Mass of one ball,
Speed of the first ball, (upward)
Mass of the other ball,
Speed of the other ball, (downward)
We know that in an inelastic collision, after the collision, both objects move with one common speed. Let it is given by V. Using the conservation of momentum to find it as :
V = 7.2 m/s
Let h is the height reached by the combined balls of putty rise above the collision point. Using the conservation of energy as :
h = 2.64 meters
So, the height reached by the combined mass is 2.64 meters. Hence, this is the required solution.