Question 2 of 10

Physics

1 answer:

Mekhanik [1.2K]3 years ago

6 0

the awnser to ur question is D

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Test yourself: 1

Dmitry_Shevchenko [17]

Answer:

F = 1500 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of all forces must be equal to the product of mass by acceleration.

ΣF = m*a

F = 1000*1.5

F = 1500 [N]

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makkiz [27]

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A 5.30kg block hangs from a spring with a spring constant 1700 N/m. The block is pulled down 4.50cm from the equilibrium positio

Andru [333]

To solve this problem it is necessary to apply the concepts related to the frequency in a spring, the conservation of energy and the total mechanical energy in the body (kinetic or potential as the case may be)

PART A) By definition the frequency in a spring is given by the equation

$f = \frac{1}{2\pi} \sqrt{\frac{k}{m}}$

Where,

m = mass

k = spring constant

Our values are,

k=1700N/m

m=5.3 kg

Replacing,

$f = \frac{1}{2\pi} \sqrt{\frac{1700}{5.3}}$

$f=2.85 Hz$

PART B) To solve this section it is necessary to apply the concepts related to the conservation of energy both potential (simple harmonic) and kinetic in the spring.

$\frac{1}{2}kA^2 = \frac{1}{2}mv^2 + \frac{1}{2} kY^2$