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Iteru [2.4K]
3 years ago
8

Question 2 of 10

Physics
1 answer:
Mekhanik [1.2K]3 years ago
6 0

the awnser to ur question is D

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How can we prevent ear-problems often encountered by passengers after a flight journey?​
slamgirl [31]

<u>Follow these tips to prevent ear-problems often encountered by passengers after a flight journey:-</u>

Yawn and swallow during ascent and descent. ...

Use the Valsalva maneuver during ascent and descent. ...

Don't sleep during takeoffs and landings. ...

Reconsider travel plans. ...

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3 0
3 years ago
An example of a double reaction is
butalik [34]
C. is the only double reaction here given that a double replacement reaction involves two compounds that exchange previous components, and C is the only solution with two compounds present
8 0
4 years ago
1.) Calculate the work done in lifting a 200 N couch a distance of 1.3 m from a loading ramp.
Free_Kalibri [48]

Explanation:

work = force ×distance

1 w = ? f= 200 d= 1.3

w = f ×d

=200×1.3

= 269 joule

2 w=? f=40. d=6

w= 40/6

= 240 joule

3. w=? m=254. f= ? d=3

w=f=mg. f= 254×10. f= 2540

w=f×d

=2540×3

= 7620 joule

8 0
4 years ago
Read 2 more answers
I will give brainliest) According to Newton's second law of motion, when an object is acted on by an unbalanced force, how will
evablogger [386]
Newton's<span> first </span>law of motion<span> has been frequently stated throughout this lesson. An</span>object<span> at rest stays at rest and an </span>object<span> in </span>motion<span> stays in </span>motion<span> with the same speed and in the same direction unless </span>acted<span> upon by an </span>unbalanced force<span>.</span>
4 0
4 years ago
Read 2 more answers
A uniform rod is 2. 0 m long and has mass 15 kg. What is most nearly the rod's mass moment of inertia?
trapecia [35]

The rod's mass moment of inertia is 5kgm².

<h3>Moment of Inertia:</h3>

The "sum of the product of mass" of each particle with the "square of its distance from the axis of rotation" is the formula for the moment of inertia.

The Parallel axis Theorem can be used to compute the moment of inertia about the end of the rod directly or to derive it from the center of mass expression. I = kg m². We can use the equation for I of a cylinder around its end if the thickness is not insignificant.

If we look at the rod we can assume that it is uniform. Therefore the linear density will remain constant and we have;

or = M / L = dm / dl

dm = (M / L) dl

I =  \int\limits^M_0 {r^2} \, dm

I = \int\limits^\frac{L}{2} _\frac{-L}{2}  {I^2 (M/L)} \, dl

Here the variable of the integration is the length (dl). The limits have changed from M to the required fraction of L.

I = \int\limits^\frac{L}{2} _\frac{-L}{2}  {I^2 (M/L)} \, dl

I = \frac{M}3L}[(\frac{L^3}{2^3}   - \frac{-L^3}{2^3} )]\\\\I = \frac{1}{12}ML^2

Mass of the rod = 15 kg

Length of the rod = 2.0 m

Moment of Inertia, I = \frac{1}{12}15 (2)^2

                               = 5 kgm²

Therefore, the moment of inertia is 5kgm².

Learn more about moment of inertia here:

brainly.com/question/14119750

#SPJ4

4 0
2 years ago
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