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motikmotik
2 years ago
7

Please help!! Physics homework

Physics
1 answer:
kogti [31]2 years ago
6 0

Answer:

Give up.

Explanation:

Physics is horrible.

And that's the cold hard truth. :(

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A pickup truck is traveling down the highway at a steady speed of 30.1 m/s. The truck has a drag coefficient of 0.45 and a cross
Sav [38]

Answer:

The energy that the truck lose to air resistance per hour is 87.47MJ

Explanation:

To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

F_D=\frac{1}{2}\rhoC_dAV^2

Our values are:

V=30.1m/s

C_d=0.45

A=3.3m^2

\rho=1.2kg/m^3

Replacing,

F_D=\frac{1}{2}(1.2)(0.45)(3.3)(30.1)^2

F_D=807.25N

We need calculate now the energy lost through a time T, then,

W = F_D d

But we know that d is equal to

d=vt

Where

v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,

W=(807.25N)(30.1m/s)(3600s/1hr)

W=87.47*10^6J (per hour)

Therefore the energy that the truck lose to air resistance per hour is 87.47MJ

4 0
3 years ago
The teacher shared a demonstration with the same students. She begin by standing on a desk, holding a book and an open piece of
bazaltina [42]

Answer:

I think its c

Explanation:

7 0
3 years ago
Some of the quantities you measure in this lab are vectors and some are scalers. When you add vectors together youneed to worry
GalinKa [24]

Answer:

B I think

Explanation:

4 0
3 years ago
A car is driving towards an intersection when the light turns red. The brakes apply a constant force of 1,398 newtons to bring t
dmitriy555 [2]

Answer:

the initial velocity of the car is 12.04 m/s

Explanation:

Given;

force applied by the break, f = 1,398 N

distance moved by the car before stopping, d = 25 m

weight of the car, W = 4,729 N

The mass of the car is calculated as;

W = mg

m = W/g

m = (4,729) / (9.81)

m = 482.06 kg

The deceleration of the car when the force was applied;

-F = ma

a = -F/m

a = -1,398 / 482.06

a = -2.9 m/s²

The initial velocity of the car is calculated as;

v² = u² + 2ad

where;

v is the final velocity of the car at the point it stops = 0

u is the initial velocity of the car before the break was applied

0 = u² + 2(-a)d

0 = u² - 2ad

u² = 2ad

u = √2ad

u = √(2 x 2.9 x 25)

u =√(145)

u = 12.04 m/s

Therefore, the initial velocity of the car is 12.04 m/s

7 0
2 years ago
HELP!! TWO QUESTIONS FAST AND BRAINLIEST
IRINA_888 [86]

Answer:

1. The standard metric unit of momentum is the kg•m/s.

2. the units of momentum will be the product of the units of mass and velocity. Mass is measured in kg and velocity in ms-1, therefore, the SI unit of momentum will be kgm/s(-1).

3.Recall that acceleration is rate of change of velocity, so we can rewrite the Second Law: force = mass x rate of change of velocity. Now, the momentum is mv, mass x velocity. ... rate of change of momentum = mass x rate of change of velocity.

Explanation:

i really hope i helped sorry for the paragraphs ;( !

6 0
3 years ago
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