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Lesechka [4]
3 years ago
14

6–3 The current through a 0.1‐μF capacitor is a rectangular pulse with an amplitude of 2 mA and a duration of 5 ms. Find the cap

acitor voltage at the end of the pulse when the capacitor voltage at the beginning of the pulse is –1 V.
Physics
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

999 V

Explanation:

Charge deposited on the capacitor

= current x time  

= 2 x 10⁻³ A x 5 x 10⁻³

=  10⁻⁵ C

increase in volt = charge deposited / capacitance

10⁻⁵ / .1 x 10⁻⁶

= 10² V

= 100 V

voltage in the beginning = -1 V

voltage at the end

= -1 + 100

99 V .

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Answer:

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Explanation:

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3 years ago
You throw a 3.00 N rock vertically into the air from ground level. You observe that when it is 16.0 m above the ground, it is tr
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Answer:

The final speed of the stone as it lift the ground is 23.86 m/s.            

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Given that,

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We need to find the rock's speed just as it left the ground. It can be calculated using work energy theorem as :

W=\Delta E\\\\W=\dfrac{1}{2}m(v^2-u^2)\\\\Fd=\dfrac{1}{2}m(v^2-u^2)\\\\v^2=\dfrac{2Fd}{m}+u^2\\\\v^2=\dfrac{2mgd}{m}+u^2\\\\v^2=2\times 9.8\times 16+(16)^2\\\\v=23.86\ m/s

So, the final speed of the stone as it lift the ground is 23.86 m/s.                                                    

4 0
3 years ago
¿que acciones o actitudes de tiempo de inmovilizacion obligatoria descubrimos o hemos fortalecido en casa con familia?
kap26 [50]

Answer:

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Calculate the pressure in SI unit when a force of 100 dyne acts on area of 0.02cm²​
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Answer:

500 Pa

Explanation:

Convert given units to SI:

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Ber [7]

Answer:

D.)

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