1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aliina [53]
3 years ago
6

A mass attached to a 50.0 cm long string starts from rest and is rotated 40 times in one minute before reaching a final angular

speed. Determine the angular acceleration of the mass, assuming that it is constant.
Physics
1 answer:
ch4aika [34]3 years ago
4 0

To solve this problem it is only necessary to apply the kinematic equations of angular motion description, for this purpose we know by definition that,

\theta = \frac{1}{2}\alpha t^2 +\omega_0 t + \theta_0

Where,

\theta = Angular Displacement

\alpha =Angular Acceleration

\omega_0 = Angular velocity

\theta_0 =Initial angular displacement

For this case we have neither angular velocity nor initial angular displacement, then

\theta = \frac{1}{2}\alpha t^2

Re-arrange for \alpha,

\alpha = \frac{2\theta}{t^2}

Replacing our values,

\alpha = \frac{2(40rev*\frac{2\pi rad}{1rev})}{60^2}

\alpha = 0.139rad/s

Therefore the ANgular acceleration of the mass is 0.139rad/s^2

You might be interested in
Daisy made the graph shown to display the data recorded during an experiment. Daisy is studying the effect of soil on the growth
andreev551 [17]

im in flvs too if thats what this is but anyway im doing it right now and i believe it is sunlight was not kept constant


3 0
3 years ago
Read 2 more answers
Two ice skaters, each with a mass of 72.0 kg, are skating at 5.45 m/s when they collide and stick together. If the angle between
Rudiy27

Answer:

The skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.

Explanation:

To solve the problem it is necessary to go back to the theory of conservation of momentum, specifically in relation to the collision of bodies. In this case both have different addresses, consideration that will be understood later.

By definition it is known that the conservation of the moment is given by:

m_1v_1+m_2v_2=(m_1+m_2)v_f

Our values are given by,

m_1=m_2=72Kg

As the skater 1 run in x direction, there is not component in Y direction. Then,

Skate 1:

v_{x1}=5.45m/s

v_{y1}=0

Skate 2:

v_{x2} = 5.45*cos105= -1.41m/s

v_{y2} = 5.45*sin105 = 5.26m/s

Then, if we applying the formula in X direction:

m_1v_{x1}+m_2v_{x2}=(m_1+m_2)v_{fx}

75*5.45-75*1.41=(75+75)v_{fx}

Re-arrange and solving for v_{fx}

v_{fx}=\frac{4.04}{2}

v_{fx}=2.02m/s

Now applying the formula in Y direction:

m_1v_{y1}+m_2v_{y2}=(m_1+m_2)v_{fy}

0+75*5.25=(75+75)v_{fy}

v_{fy}=\frac{5.25}{2}

v_{fy}=2.63m/s

Therefore the skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.

6 0
3 years ago
If you weighed 130 pounds on earth, you would weigh _____pounds on the moon
Aneli [31]

Answer:

152 pounds

Explanation:

4 0
3 years ago
A 0.5 kg rock is dropped from a height of 1.0 m above the ground. Approximately how much kinetic energy will be stored in the ro
irina1246 [14]

Answer:

2.45 J

Explanation:

The following data were obtained from the question:

Mass (m) = 0.5 kg

Height (h) = 1 m

Kinetic energy (KE) =?

Next, we shall determine the velocity of the rock after it has fallen half way. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 1/2 = 0.5 m

Final velocity (v) =?

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 0.5)

v² = 9.8

Take the square root of both side

v = √9.8

v = 3.13 m/s

Finally, we shall determine the kinetic energy of the rock after it has fallen half way. This can be obtained as follow:

Mass (m) = 0.5 kg

Velocity (v) = 3.13 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.5 × 3.13²

KE = 0.25 × 9.8

KE = 2.45 J

Therefore, the kinetic energy of the rock after it has fallen half way is 2.45 J

8 0
3 years ago
How are light waves used to bring far away objects into view and how does the eye translate them?
adelina 88 [10]

Answer:

When focused light is projected onto the retina, it stimulates the rods and cones. The retina then sends nerve signals are sent through the back of the eye to the optic nerve. The optic nerve carries these signals to the brain, which interprets them as visual images.

Explanation:

Hope it will help u

5 0
2 years ago
Other questions:
  • Cellular phones use _____?
    12·2 answers
  • A stone is thrown upward at an angle. what happens to the horizontal component of its velocity as it rises? as it falls?
    13·1 answer
  • An electron is accelrated by a unifor electric field (1000v/m) pointing vertically upward. Use energy methods to get the magnitu
    7·1 answer
  • If a negative charge is initially at rest in an electric field, will it move toward a region of higher potential or lower potenti
    8·1 answer
  • In a hydraulic system, a 100.-newton force is applied to a small piston with an area of 0.0020 m2 . What pressure, in pascals, w
    13·2 answers
  • Which method of separation would you use when working in the garden and trying to separate the dirt from the weeds?
    10·2 answers
  • The air speed of a plane is defined as its velocity with respect to the surrounding air, or in other words how fast the plane wo
    8·1 answer
  • suppose a scientist found a new matal-like substance in the desert. He determined its mass to be 20 grams. The volume was determ
    12·1 answer
  • A small sphere of reference-grade iron with a specific heat of 447 J/kg K and a mass of 0.515 kg is suddenly immersed in a water
    14·1 answer
  • Particles in a liquid______, move about, and ______
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!