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aliina [53]
3 years ago
6

A mass attached to a 50.0 cm long string starts from rest and is rotated 40 times in one minute before reaching a final angular

speed. Determine the angular acceleration of the mass, assuming that it is constant.
Physics
1 answer:
ch4aika [34]3 years ago
4 0

To solve this problem it is only necessary to apply the kinematic equations of angular motion description, for this purpose we know by definition that,

\theta = \frac{1}{2}\alpha t^2 +\omega_0 t + \theta_0

Where,

\theta = Angular Displacement

\alpha =Angular Acceleration

\omega_0 = Angular velocity

\theta_0 =Initial angular displacement

For this case we have neither angular velocity nor initial angular displacement, then

\theta = \frac{1}{2}\alpha t^2

Re-arrange for \alpha,

\alpha = \frac{2\theta}{t^2}

Replacing our values,

\alpha = \frac{2(40rev*\frac{2\pi rad}{1rev})}{60^2}

\alpha = 0.139rad/s

Therefore the ANgular acceleration of the mass is 0.139rad/s^2

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The long structure of small intestine is accommodated in small space within our body. Comment.
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6 0
1 year ago
Normally, jet engines push air out the back of the engine, resulting in forward thrust, but commercial aircraft often have thrus
ANEK [815]

Answer:

When the ejected air is moving in the downward direction then the thrust force acts in the upward direction, due to reversal thrust, the jets can take off vertically without needing a runway this way.

Explanation:

Newton’s third law motion states that for every action there will be an equal and opposite reaction.

Thrust reversal is also known as reverse thrust. It acts opposite to the motion of the aircraft by providing the deceleration.

Commercial aircraft moves the ejected air in the forward direction means that the thrust will acts opposite to the motion of the aircraft that is backward direction due to thrust reversal. This thrust force might be used to decelerate the craft.

Uses of thrust reversal in practice:

When the ejected air is moving forward direction then the thrust force moving backward direction due to reversal thrust the speed of the craft slows down.

When the ejected air is moving in the downward direction then the thrust force acts in the upward direction, due to reversal thrust, the jets can take off vertically without needing a runway this way.

6 0
3 years ago
If the mass of the body is doubled what should be its speed so as to maintain the same kinetic energy ?​
soldier1979 [14.2K]

Answer:

The speed should be reduced by 1/√2 or 0.707 times

Explanation:

The relationship between the kinetic energy, mass and velocity can be represented by the following equation:

K.E = ½m.v²

In this equation, the mass is inversely proportional to the square of the velocity or speed. This means that as the mass increases, the speed reduces by × 2.

Let; initial mass = m1

Final mass = m2

Initial velocity = v1

Final velocity = v2

According to the question, if the mass of the body is doubled i.e. m2 = 2m

½m1v1² = ½m2v2²

½ × m × v1² = ½ × 2m × v2²

Multiply both sides by 2

(½ × m × v1²)2 = (½ × 2m × v2²)2

m × v1² = 2m × v2²

Divide both sides by m

v1² = 2v2²

Divide both sides by 2

v1²/2= v2²

Square root both sides

√v1²/2= √v2²

v1/√2 = v2

v2 = 1/√2 v1

This shows that to maintain the same kinetic energy if the mass is doubled, the speed should be reduced by 1/√2 or 0.707 times.

8 0
2 years ago
Find the moment of inertia of a hoop (a thin-walled, hollow ring) with mass M and radius R about an axis perpendicular to the ho
mote1985 [20]

Answer:

 I = 2 MR²

Explanation:

Given that

Radius of the hollow ring ( hoop ) = R

The mass of the hoop = M

We know that mass moment of inertia of a hoop about its center is given as

Io= M R²

By using theorem  ,mass moment of inertia at distance d from center is given as

I= Io + m d²

Here ,M= m  ,d =R

Now by putting the values in the above equation we get

I =  M R² +  M R²

I = 2 MR²

Therefore the mass moment of inertia will be  2 M R².

7 0
3 years ago
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